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1) √12
√48
2)√5
√80
3) √12
√156
4) √7
√63
(The top surd divide by the bottom one)
I know how to rationalise the denominator of simple surds but these are the difficult ones.
Could someone please help and explain how they got to the final answer.
Thank you

2007-07-25 06:12:57 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

1) √12/√48 = √(12/48) =√(1/4)=1/2
2) √5/√80 = √(5/80) = √(1/16) = 1/4
3) √12/√156 = √(1/13)= √13/13
4) √(7/63) =√(1/9) 1/3

2007-07-25 06:21:34 · answer #1 · answered by xandyone 5 · 0 0

1) √12 / √48 = 1/√4 = 1/2 or -1/2

2)√5 / √80 = 1 / √16 = 1/4 or -1/4
3) √12 / √156 = 1 / √13
4) √7 / √63 = 1 / √9 = 1/3 or -1/3

The procedure is simple. Find the fractions of the denominator and id the numerator and denominator are common, cancel them out and see whether the balance root is an integer.

2007-07-25 13:35:27 · answer #2 · answered by Swamy 7 · 0 0

This will help you... √(ab)=√a√b

1) √12/√48 = √12/(√12√4)=1/2 after cancelling the √12 and dealing with √4=2.

2)√5/√80 = √5/(√5√16)= 1/4 after cancelling √5...

Can you figure it out from here? Factor the denominators.

3) √12/√156

4) √7/√63

2007-07-25 13:23:48 · answer #3 · answered by Jason K 2 · 0 0

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