18x^5y^4 + 9x^3y^2 - 3xy
----------------------------------
3xy
2007-07-25 06:11:59 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
divide 3 from the top and bottom
(6x^5y^4 + 3x^3y^2 - xy)/xy
factor out xy from the top
xy(6x^4y^3 + 3x^2y - 1)/xy
simplify
6x^4y^3 + 3x^2y - 1
2007-07-25 06:16:27 · answer #1 · answered by sam l 3 · 0⤊ 0⤋
6 x^4 y³ + 3 x² y - 1
2007-07-26 17:36:43 · answer #2 · answered by Como 7 · 0⤊ 0⤋
You need to factor the numerator first.
[3xy(6x^4y^3 + 3x^2y - 1)] / (3xy)
Now, the 3xy cancels in numerator and denominator.
You are left with:
6x^4y^3 + 3x^2y - 1
2007-07-25 13:16:15 · answer #3 · answered by its_victoria08 6 · 0⤊ 0⤋
Did you know that
2 + 3
---------
7
is the same as
2/7 + 3/7
Also did you know that
x^5 is x times x with 5 x's.
Did you know that
x times x times x
-----------------------
x times x
is
x
And your answer also is:
6x^4y^3 + 3x^2y - 1
The one at the end is from the -3xy / 3xy.
Funny it's not zero, huh?
2007-07-25 13:24:19 · answer #4 · answered by winter_new_hampshire 4 · 0⤊ 0⤋
6x^4y^3 + 3x^2y - 1
2007-07-25 13:15:01 · answer #5 · answered by Anonymous · 0⤊ 1⤋
6x^4y^3 + 3x^2y -1
2007-07-25 13:16:08 · answer #6 · answered by thomas 7 · 0⤊ 1⤋
6x^4y^3+3x^2y-1
2007-07-25 13:16:08 · answer #7 · answered by Joe P 2 · 0⤊ 1⤋
its confusing the way u typed it in type it in a non confusing way used spaces between each full number thingy
2007-07-25 13:16:04 · answer #8 · answered by Anonymous · 0⤊ 1⤋
Uhhh....WHAT???
2007-07-25 13:15:17 · answer #9 · answered by Gabe 3 · 0⤊ 1⤋
27x+8y+6-3xy
your welcome
2007-07-25 13:16:56 · answer #10 · answered by PickleLvR 2 · 0⤊ 0⤋