2007-07-25 04:55:22 · 4 answers · asked by Virtuous Woman 1 in Science & Mathematics ➔ Mathematics
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2x - 3y = 6
y = 2/3x - 2
which has a slope of 2/3.
Thus the perpendicular line must have a slope of -3/2
(y - 2)/(x - 0) = -3/2
2y - 4 = -3x
y = -3/2x + 2
2007-07-25 05:03:59 · answer #1 · answered by sweetwater 7 · 1⤊ 0⤋
Given line:-
3y = 2x - 6
y = (2/3) x - 2
Gradient of perpendicular line is (- 3 / 2) and this line passes thro` (0 , 2)
y - 2 = (- 3 / 2) (x - 0)
y - 2 = (- 3 / 2) x
y = (- 3 / 2) x + 2
2007-07-25 05:08:12 · answer #2 · answered by Como 7 · 0⤊ 0⤋
discover the slopes of the two "sides" (i will assume they are lines). while 2 lines are perpendicular, their slopes are adverse RECIPROCALS. which capacity, as an occasion, if one has a slope of three, the perpendicular to it has a slope of -a million/3. enable's discover those slopes with (difference in y's) divided by using (difference in x's). the 1st "side" has a slope of three/9 whis is in basic terms a million/3. the 2nd has a slope of 15/-5 it is -3. so they are certainly perpendicular.
2016-12-14 17:45:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
perpendicular lines have product of slopes -1
(2/3).m=-1
m=-3/2
(2-y)=-3/2(0-x)
y-2=3/2(-x)
2y-4=-3x
3x-2y+4=0
there for e it is the equation
2007-07-25 05:00:08 · answer #4 · answered by srinu710 4 · 0⤊ 0⤋