Sorry you are losing your mind!!
Anyway
For part a) the discriminant is b²-4ac = 16-16 = 0.
For part b). The graph of y = 4x²+4x+4 would
be tangent to the x-axis at x = -2, so it would
have 1 x-intercept.
Try graphing this equation on a graphing calculator.
Hope that helps.
2007-07-25 02:58:35
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answer #1
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answered by steiner1745 7
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The discriminant for a quadratic is equal to b² - 4ac. Also, you have 3 cases regarding the sign of the discriminant, which we will call D, which are:
if negative (D < 0), there are zero x-intercepts
if D = 0, there is one x-intercept
if positive (D > 0), there are two x-intercepts
a) a = 1, b = 4, c = 4
b² - 4ac = 4² - 4(1)(4) = 16-16 = 0
b) Therefore, there is exactly ONE x-incercept.
2007-07-25 09:20:51
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answer #2
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answered by C-Wryte 4
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D= b^2-4ac
Where, a=1, b=4, c=4.
So,
D= 4(4)-4(1)(4)
=0.
If D=0, then there is one x-intercept.
*If D is positive, there are 2 x-intercerpts.
*If D is negative, there are no x-intercepts.
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2007-07-25 09:26:09
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answer #3
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answered by Popo B 3
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ax^2 + bx + c = 0
Discriminant (D)= b^2 - 4ac
If D > 0 you will have two distinct roots (two x-intercepts)
If D = 0 you will have two equal real roots (sometimes referred to as just one root) - (one x-intercept)
If D < 0 you will have no real roots (no x-intercepts)
a = 1
b = 4
c = 4
D = b^2 - 4ac
= 4^2 - 4*1*4
= 16 - 16
= 0
You will have one x-intercept.
2007-07-25 09:27:23
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answer #4
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answered by gudspeling 7
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None. The nearest the x axis is x=-1 , 1+(-4)+4=1
y is always greater than 0.
2007-07-25 09:26:03
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answer #5
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answered by Crushed Ice 2
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2 becuase the power of the discriminat is 2 or the power
2007-07-25 09:21:33
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answer #6
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answered by shoe soul 2
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Out of my mind, be back in 5 min.s
2007-07-25 09:21:02
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answer #7
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answered by Anonymous
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Yep, you sure are losing your mind!
2007-07-25 09:21:17
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answer #8
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answered by -R 4
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