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a) Calculate the value of the discriminant of x²+4x+4=0

b) By examining the sign of the discriminant in part a, how many x- intercepts would the graph of y=x²+4x+4 have? why?

2007-07-25 02:18:29 · 8 answers · asked by DEE H 1 in Science & Mathematics Mathematics

8 answers

Sorry you are losing your mind!!
Anyway
For part a) the discriminant is b²-4ac = 16-16 = 0.
For part b). The graph of y = 4x²+4x+4 would
be tangent to the x-axis at x = -2, so it would
have 1 x-intercept.
Try graphing this equation on a graphing calculator.
Hope that helps.

2007-07-25 02:58:35 · answer #1 · answered by steiner1745 7 · 0 0

The discriminant for a quadratic is equal to b² - 4ac. Also, you have 3 cases regarding the sign of the discriminant, which we will call D, which are:

if negative (D < 0), there are zero x-intercepts
if D = 0, there is one x-intercept
if positive (D > 0), there are two x-intercepts

a) a = 1, b = 4, c = 4

b² - 4ac = 4² - 4(1)(4) = 16-16 = 0

b) Therefore, there is exactly ONE x-incercept.

2007-07-25 09:20:51 · answer #2 · answered by C-Wryte 4 · 0 1

D= b^2-4ac

Where, a=1, b=4, c=4.

So,

D= 4(4)-4(1)(4)
=0.

If D=0, then there is one x-intercept.

*If D is positive, there are 2 x-intercerpts.
*If D is negative, there are no x-intercepts.

-//-//-

2007-07-25 09:26:09 · answer #3 · answered by Popo B 3 · 0 0

ax^2 + bx + c = 0
Discriminant (D)= b^2 - 4ac

If D > 0 you will have two distinct roots (two x-intercepts)
If D = 0 you will have two equal real roots (sometimes referred to as just one root) - (one x-intercept)
If D < 0 you will have no real roots (no x-intercepts)

a = 1
b = 4
c = 4

D = b^2 - 4ac
= 4^2 - 4*1*4
= 16 - 16
= 0

You will have one x-intercept.

2007-07-25 09:27:23 · answer #4 · answered by gudspeling 7 · 0 0

None. The nearest the x axis is x=-1 , 1+(-4)+4=1
y is always greater than 0.

2007-07-25 09:26:03 · answer #5 · answered by Crushed Ice 2 · 0 2

2 becuase the power of the discriminat is 2 or the power

2007-07-25 09:21:33 · answer #6 · answered by shoe soul 2 · 0 2

Out of my mind, be back in 5 min.s

2007-07-25 09:21:02 · answer #7 · answered by Anonymous · 0 2

Yep, you sure are losing your mind!

2007-07-25 09:21:17 · answer #8 · answered by -R 4 · 0 2

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