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2007-07-25 01:07:30 · 12 answers · asked by deannahndrsn 2 in Science & Mathematics Mathematics

12 answers

2√[ 48 ] + 7√[12] - √[ 27 ]

Remove brackets

2√48 + 7√12 - √27

2 √16 √3 + 7√4√3 - √9 √3

2 x 4 √3 + 7 x 2 √3 - 3√3

8√3 + 14√3 - 3√3

8 + 14 - 3√3

19√3

- - - - - - - - -s-

2007-07-25 01:32:25 · answer #1 · answered by SAMUEL D 7 · 1 0

2√48 = 8√3
7√12 = 14√3
- √27 = - 3√3
Total = 8√3 + 14√3 - 3√3
Total = 19√3

2007-07-26 06:03:41 · answer #2 · answered by Como 7 · 1 0

2 rt 48 + 7 rt 12 - rt 27

2 rt16 * 3 + 7 rt 4 * 3 - rt 9 * 3

2*4rt3 + 7*2rt3 - 3rt3

8rt3 +14rt3 -3rt3

22rt3 - 3rt3

19rt3

2007-07-25 01:11:36 · answer #3 · answered by Anonymous · 0 0

Hi,here is ur answer
=2√{16*3} +7√{4*3}-√{9*3}
=2*4√3 +7*2√3-3√3
=8√3+14√3-3√3
=19√3

You do like above

2007-07-25 01:16:13 · answer #4 · answered by Man of Doubts 2 · 0 1

Let's see, the square root of 48 can also be written as the square root of (3 times 16) soooo 4 radical 3, and 4 times 2 is 8.... so 8rad(3).

the square root of 12 is really the square root of (4 times 3) which is 2 radical 3, so 14rad(3).

and radical 27 is the same at radical (9 times 3) which is 3rad(3).

8(rad3)+14(rad3)-3(rad3) is = (8+14-3)(rad3) = 19rad3.

I'm a high school math teacher. :]

ps - just in case, "radical" means the same thing as "square root of"

2007-07-25 01:14:21 · answer #5 · answered by dt. 2 · 0 0

1. Find a common factor in the roots (3 in this case)
2. (2)(√3)(√16) + (7)(√3)(√4) -(√3)(√9)
3. Find roots
4. (2)(4)(√3) + (7)(2)(√3) - (3)(√3)
5. 8(√3) + 14(√3) - 3(√3)
6. Add the like terms
7.19(√3)

2007-07-25 01:12:29 · answer #6 · answered by J H 2 · 0 1

You can simplify it to:

8√3 + 14√3 - 3√3

and simplify that to:

19√3

2007-07-25 01:11:21 · answer #7 · answered by Anonymous · 1 0

2√[48] + 7√[12] - √[27] =

2√[16 x 3] + 7√[4x3] - √[9x3] =

(2x4)√[3] + (2x7)√[3] - 3√[3] =

8√[3] + 14√[3] - 3√[3] =

19√[3]

2007-07-25 01:12:38 · answer #8 · answered by Mitchell . 5 · 0 1

the first step is to find the prime factors of every number in a radical. 2√[2x2x2x2x3]+7√[2x2x3]-√[3x3x3]

Now you can take out any pairs of factors, in this case 2x2, 2x2, 2x2, and 3x3. when you take them out, don't keep the pair; only use one of the numbers. multiply it by the number outside the radical. in the case of √[3x3x3] that number can be thought of as one.


now you have only the number 3 in a radical. √3 can be treated almost like a variable. simply add 8 and 14, and subtract 3.

8√3 + 14√3 - 3√3=

19√3

2007-07-25 01:12:10 · answer #9 · answered by Anonymous · 0 1

this=2x4xsqrt[3]+7x2xsqrt[3]-3xsqrt[3].
=19sqrt[3].ANS

2007-07-25 01:23:33 · answer #10 · answered by Anonymous · 0 0

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