Factorisation?

Question

How do you factorise 48 -24a +16b -8ab?

Answer 1

48 - 24a + 16b - 8ab =

Group factor

(48 - 24a) + (16b - 8ab) =

24(2 - a) + 8b(2 - a) =

(24 + 8b)(2 - a)

- - - - - - - -s-

Answer 2

The best way is to start with the last number. In order to get -8ab you have to have either of these sets of numbers (1 / 8) or (2/4) and one of the two has to be negative. One number will have to have an A and one have a B also.

Given that the first number is 48 and not negative, it looks like the bigger number is going to have to be positive. Also, the negative is going with the A because the other negative in the equation is -24a

After that its trial and error.

If you go with 8b and -1a as the options you end up with:

(x + 8b)(y - 1a)

Somehow the numbers for x and y have to multiply together to be 48, so the options are 1/48, 2/24, 3/16, 4/12, 6/8. Plug them in and see if you can make the numbers work.

in order for the -1a to multiply by something to get -24a it looks like it needs to be 24, so I put 24 across from it and 2 in the other slot since that goes with 24 to make 48.

(24 + 8b)(2 - 1a)

Multiplying that out you get
24 x 2 = 48
24 x -1a = - 24a
8b x 2 = 16b
8b x -1a = -8ab

Done.

Raiddinn Beatdropper

Answer 3

48 - 24a + 16b - 8ab

The factors are:
(a - 2) * (b + 3) * 8

Answer 4

48 - 24a + 16b - 8ab =
24(2 - a) + 8b(2 - a) =
(24 + 8b)(2 - a)

Answer 5

48 -24a +16b -8ab
= 8(6 - 3a + 2b - ab)
= 8(6 + 2b - 3a - ab)
= 8(2(3+b) - a(3+b))
= 8(2-a)(3+b)

Answer 6

48 - 24a+16b - 8ab

24(2-a) + 8b(2-a)

hang on... lol thats all i can remember

Answer 7

48-24a+16b-8ab=24*(2-a)+8b*(2-a)
=(2-a)(24+8b)
=8(2-a)(3+b).ANS.