Alice has 357 apples in her 5 baskets. She was able to carry 3 of them. The first basket contains 80 apples. 64 for the second and third. The 4th basket contains 1/2 of the sum of apples the first three baskets.
How many apples does the last basket contain?
How many apples will each basket have if divided equally?
Alice ate the remainder of the apples. How many apples did she ate?
How many apples does the 4th basket have (not yet divided)?
First person to get all questions get the points!
2007-07-14 22:24:38 · 5 answers · asked by karlo de guzman 3 in Science & Mathematics ➔ Mathematics
1st basket: 80 apples
2nd basket: 64 apples
3rd basket: 64 apples
4th basket: (1/2)(80+64+64)=104 apples
5th basket: 357-(80+64+64+104) = 45 apples
357 mod 5 = 2
Alice ate 2 apples
If the apples are divided equally (after Alice eats those 2 apples) each basket will have 355/5 = 71 apples.
2007-07-14 22:36:36 · answer #1 · answered by gudspeling 7 · 0⤊ 0⤋
How many apples does the last basket contain?
357 - ( [80 + 64 + 64] + [0.5 * {80 + 64 + 64}])
357 - (208 + [0.5 * 208])
357 - (208 + 104)
357 - 312
45
How many apples will each basket have if divided equally?
71 each
How many are the remainder of apples that she ate?
357 - (71 * 5)
357 - 355
2
How many does the 4th basket have before dividing?
1/2 * (80 + 64 + 64)
1/2 * 208
104
2007-07-15 05:56:54 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
80+64+64=208 apples in first 3 baskets so 357-208=149 left
1/2 of 208 is 104 in basket 4 so basket 5 has 149-104=45 apples.
for equal division 357/5= 71.4 apples
if Alice eats the remainders .4x5= 2 apples
2007-07-15 05:36:52 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋
Q1. 357-(144+72) =141
Q2. 71
Q3. 2
Q4.basket 1 +b 2+b3
80+64=144
basket#4 144/2=72
2007-07-15 05:37:24 · answer #4 · answered by Twinky 3 · 0⤊ 0⤋
Last basket = 45
Equally = 71 (2 left)
Ate = 2
4th = 104
2007-07-15 05:37:22 · answer #5 · answered by luvourpaps 2 · 0⤊ 0⤋