Write each equation in standard form.
1) y-2=3(x-5)
2) y-5=4/3(x-3)
Please show solution and thanks.
2007-07-14 21:00:19 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The standard form is: y = mx +b wher m is the slope of the line, and b is the y-intercept.
1) y-2=3(x-5)
y = 3x -13
2)y-5=4/3(x-3)
y = 5 +(4/3)x -4
y = (4/3)x +1
2007-07-14 21:07:41 · answer #1 · answered by cscokid77 3 · 0⤊ 1⤋
1) From the given equation you can tell that it is a straight line, from the equation y=mx+c, m is the gradient of the line and 'c' is where the line cuts the y-axis in other words y-intercept.....
y-2=3(x-5)
y-2=3x-15
y=3x-15+2
y=3x-13
2)y-5=4/3(x-3)
y-5=4x/3-4
y=4x/3-4+5
y=4x/3+1
2007-07-15 07:15:36 · answer #2 · answered by Jack C 2 · 0⤊ 0⤋
Question 1
y - 2 = 3x - 15
y = 3x - 15 + 2
y = 3x - 13
or
3x - y - 13 = 0
Question 2
Reading this as:-
y - 5 = (4/3) (x - 3)
3y - 15 = 4 (x - 3)
3y - 15 = 4x - 12
3y = 4x + 3
y = (4/3) x + 1
or
3y = 4x + 3
4x - 3y + 3 = 0
2007-07-15 04:25:26 · answer #3 · answered by Como 7 · 0⤊ 0⤋
1.) y-2=3(x-5)
y-2=3x-15
y-2+2=3x-15+2 (add both sides by 2)
y=3x-13
2.) y-5=4/3(x-3)
y-5=4/3x-4
y-5+5=4/3x-4+5 (add both sides by 5)
y=4/3x+1
2007-07-15 04:10:03 · answer #4 · answered by Anonymous · 0⤊ 1⤋
1)
y-2=3(x-5)
y-2=3x-15
15-2=3x-y
3x-y-13=0
(ax+by+c=0)
2)
y-5=4/3(x-3)
3(y-5)=4(x-3)
3y-15=4x-12
-15+12=4x-3y
-3=4x-3y
4x-3y+3=0
(ax+by+c=0)
2007-07-15 04:13:15 · answer #5 · answered by talib_the_terror 2 · 0⤊ 0⤋
i'm too clever to do this simple equation.......!@#$#%
By the way.....i don't know the solution.....(He 3x)
2007-07-15 04:04:51 · answer #6 · answered by brokn_shatters 1 · 0⤊ 3⤋