If r and s are positive integers and (1/r) + s = 1, then what is the value of s in terms of r?
a) (r-1)/r
b) (1-r)/r
c) (1-r)/(1+r)
d) r/(1+r)
e) r/(r-1)
[4a - (2/3)] / 2 =?
a) 2a - (4/a)
b) 2a - 1
c) 2a - (2/3)
d) 2a - (1/3)
e) 8a - (4/3)
plz explain or show work
2007-07-14 19:27:10 · 5 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
(1/r) + s = 1
We want to isolate s.
s = 1 - (1/r)
Create a common denominator.
s = (r/r) - (1/r)
s = (r - 1)/r
2007-07-14 19:31:17 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
1) s=1-1/r=(r-1)/r Answer A
2)[4a-(2/3)]/2=(4a/2)-(2/3)/2
=2a-2/6=2a-(1/3) Answer D
2007-07-15 02:32:34 · answer #2 · answered by Red_Wings_For_Cup 3 · 0⤊ 0⤋
1. Ans = (a)
(1/r) + s = 1 =>
s = 1 - 1/r
= (r - 1)/r
2. Ans =
[4a - (2/3)] / 2
= 4a/2 - (2/3)/2 (expanding braces)
= 2a - 1/3 (dividing individually)
2007-07-15 02:58:46 · answer #3 · answered by Sam 1 · 0⤊ 0⤋
(1/r) + s = 1
s = 1 - (1/r)
s = r/r - 1/r
s = (r - 1)/r
[4a - (2/3)] / 2 =
4a/2 - (2/3)(1/2) =
2a - (1/3)
2007-07-15 02:39:55 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
(1/r) + s = 1
s = 1 - (1/r)
s = (r/r) - (1/r)
s = (r - 1)/r
2007-07-15 02:52:54 · answer #5 · answered by Anonymous · 0⤊ 0⤋