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Find each value of θ to the nearest degree:

a) csc θ = 1.624
b) cot θ = 0.675
sec θ = 1.058


i know this is probably really really easy but i haent dun trig in like 2 years!!

***and how do you type this in a calculator??********

show work please

thx


oh and ALSO...

what does find the 6 trigonmetric rations of A in the given traignle mean? they give me a right angle triangle named ABC. the adjacent is 5, opp is 12.

then the questions are... sin A= ?, cosA=? cotA=? cscA=?

2007-07-14 15:54:11 · 6 answers · asked by mystery_girl07 2 in Science & Mathematics Mathematics

6 answers

Remember these identities, they will be your lifesavers:

csc=1/sin
sec=1/cos
tan=1/cot=sin/cos=1/(cos/sin)

csc(x)=1.624

So 1/sin(x)=1.624
sin(x)=1/1.624

So you find 1/1.624 and take the inverse sin of it. There should be a button on the calculator that says sin^-1 or something similar (maybe arcsin).

Same thing for the other two.

For a right triangle with angle x and 3 sides (opposite, adjacent, and hypotenuse), the trig function values are as follows:

sin(x)=opp/hyp
cos(x)=adj/hyp
tan(x)=opp/adj
csc(x)=hyp/opp
sec(x)=hyp/adj
cot(x)=adj/opp

2007-07-14 16:06:18 · answer #1 · answered by Red_Wings_For_Cup 3 · 0 0

i don't have a calculator with me, instead of theta, i will use a.

a) csc a = 1/sina , find sin a with ur calculator and take the reciprocal.

b) cot a = cosa/sina

c) sec a = 1 / cos a , same thing like part a except it's cosine.
if u have a texas instruments calculator, u type sin then the number, then the equals to sign i think because that's how my casio functions.
first u find the hypotenuse by pythagoras,

5^2+12^2= 25 + 144 => hypotenuse^2 = 169
=> hypotenuse = 13

sin A = opposite/hypotenuse = 12/13

cosA= adjacent/hypotenuse = 5/13

cotA = cosA/sinA = 5/13 / 12/13 = 5/12

cscA = 1/sinA = 1 / 12/13 = 13/12

2007-07-14 16:02:00 · answer #2 · answered by Anonymous · 0 0

csc θ = 1.624 is 1/sin θ = 1.624 or sin θ = 1/1.624
sin θ = .6090 sin^-1 (.6090)=~37.5181 find the inv sin button on your scientific calculator marked as sin to
power of -1

same for cot θ = 0.675 which is 1/ tan θ = 0.675 or
tan θ = 1/0.675 = 1.481 θ = 55.9806 using the tan^-1 button

3. ans = 19.059 knowing sec is 1/cos then using cos^-1 button


the 3rd side (Hyp) is sqrt(5^2 +12^2) = 13
sin A= 12/13
cosA= 5/13
tan A= 12/5
cscA= 13/12 flip sinA
secA= 13/5 flip cosA
and flip tanA to get cotA= 5/12

2007-07-14 16:23:36 · answer #3 · answered by 037 G 6 · 0 0

First part:
a) csc θ = 1.624
b) cot θ = 0.675
c) sec θ = 1.058

These are all reciprocal fuctions, which is not what the calculator is designed for. You have to get these to look like sin, cos, and tan. csc=1/sin, cot=1/tan, and sec=1/cos.

So, to solve, first take the reciprocal of each side.
a) 1/cscθ=1/1.624
1/cscθ=sinθ, so you have sinθ=1/1.624 or sinθ=.615764

Now you can plug it into the calculator. Usually it is the 2nd function of the trig buttons. That is, press 2nd, then sin, then type in .615764. I got 0.66335. (Radians)

Do this for all three.

Your second question:

First, you'll have to use the Pythagorean Theorem to solve for the hypotenuse.

Then, you just have to know that sin=opp/hypot, cos=adj/hypot, tan=opp/adj, csc=hypot/opp, sec=hypot/adj, and cot=adj/opp. All you have to do is show the fraction and reduce if possible.

2007-07-14 16:09:04 · answer #4 · answered by korie55 2 · 0 0

With computer the easiest way is to use Excel.

In Excel click fx (function). In the menu select category of function "Math & Trig" and then select the required function.

Use funcions ACOS (arccosinus), ASIN (arcsinus), ATAN (arctangens) and DEGREES (conversion of radians to degrees). Arccotangens, arcsecans and arccosecans are not in Excel, but it is not a problem.

Example:

b)

cot θ = 0.675

θ = arccot 0.675 = arctng (1/0.675) = 0.97704666 = 55.98065001°

And here is one link:

http://www.mathsisfun.com/sine-cosine-tangent.html

-

2007-07-14 17:00:55 · answer #5 · answered by oregfiu 7 · 0 0

i chanced on trig to be greater straightforward. Geometry in severe college became into the toughest for me, if actuality be told, I nevertheless think of severe college geometry is extremely greater sturdy than a great form of the faculty math classes i'm taking to be effortless...I disliked it very plenty.

2016-09-30 00:38:06 · answer #6 · answered by Anonymous · 0 0

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