if adam is 10,000 days older than jane, how old will jane have to be, to be 1/3 as old as adam?
2007-07-14 15:47:06 · 5 answers · asked by ftm821 2 in Science & Mathematics ➔ Mathematics
Hi,
If x = Adam's age and Jane is 1/3 as old as Adam, then her age is 1/3x. Since Adam is 10,000 days older, then the equation is
x - 1/3x = 10,000
2/3x = 10,000
2x = 30,000
x = 15,000 This is Adam's age.
1/3x = 1/3 * 15,000 = 5,000 <== Jane's age
I hope that helps!! :-)
The answer is 5,000 days !!!!!!!
2007-07-14 15:49:56 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
Let A represent Adams age in days.
Let J represent Janes age in days.
Then:
A = J + 10,000
J = A/3
Substitute 2 for J in 1
A = A/3 + 10,000
Multiply by 3 & transpose
3A - A = 30000
2A = 30000
A = 15000
Substitute in 2
J = 15000/3, J = 5000.
2007-07-14 22:57:55 · answer #2 · answered by Robert S 7 · 0⤊ 0⤋
Let x be Jane's age.
3x-x = 10,000
x = 5,000 days
2007-07-14 22:50:17 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
5000 days old or 13 years, 251 days, and 18 hours old, to be more precise.
2007-07-14 22:58:55 · answer #4 · answered by Kevin U 4 · 0⤊ 0⤋
maybe 5,000 or 6,667 days but im not sure
2007-07-14 22:52:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋