3x^2 + 11x -8?
just answer me with a YES or NO. cause i've been solving this and yet i can't get the factors.
2007-07-14 14:42:36 · 6 answers · asked by rapidgirl 2 in Science & Mathematics ➔ Mathematics
how come there are mixed answers! hhwwuuaah! it is +11.
2007-07-14 14:49:10 · update #1
if i need a whole number factors, is it still factorable?
2007-07-14 14:57:20 · update #2
Sorry for all your mixed answers.
Only 1 so far is right: The answer is NO.
You want to know if this is factorable over the
rationals. There is a simple way to tell:
ax²+bx+c is factorable over the rationals
if and only if b²-4ac is a square.
In your case, b²-4ac = 121+96 = 217.
Since this is not a square, you can't factor
your trinomial over the rationals.
2007-07-14 15:28:17 · answer #1 · answered by steiner1745 7 · 2⤊ 1⤋
Yes
2007-07-14 21:46:42 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Yes, you have to use a certain formula. I won't go any further because it seems like you actually want to do this yourself, which is good. Good luck, and let me know if you need help!
edit:
You have to use the quadratic formula to factor this. You will NOT get rational factors, but that does not mean that the function isn't factorable.
2007-07-14 21:45:48 · answer #3 · answered by whitesox09 7 · 0⤊ 2⤋
NO.
Assuming you mean factorable with integers.
The roots of it are not integers or even fractions because its discriminant (11² - 4Ã3Ã(-8) = 217) is not a square. See http://en.wikipedia.org/wiki/Discriminant
2007-07-14 21:45:47 · answer #4 · answered by сhееsеr1 7 · 2⤊ 2⤋
No, not with the signs as you have shown them.
2007-07-14 22:08:16 · answer #5 · answered by kindricko 7 · 0⤊ 0⤋
No
2007-07-14 21:47:18 · answer #6 · answered by frank 7 · 0⤊ 2⤋