Area of a rhombus??

Question

what the formula? please help?

Answer 1

1/2 times the diagonal times the other diagonal

Answer 2

There are three ways you can calculate the area of a rhombus:
(1) If you know the altitude - the vertical distance from the base to the opposite side. The area = length of the base * altitude
(2) Another way to calculate the area is if you know the lenghts of the diagonals of the rhombus. Using this information the area = 0.5 * d1 * d2
(3) The last way to calculate the area is using trigonometry. If you know the angle measurement (call it a) of any corner of the rhombus and length of one side (call it s), then the area = (s^2)* sin(a)

Answer 3

Area of a rhombus is 1/2 of the product of the diagonals.

Answer 4

Area
The area of any rhombus is a half the product of the lengths of its diagonals: A= (D1 x D2)/2

Because the rhombus is a parallelogram with four equal sides, the area also equals the length of a side (B) multiplied by the perpendicular distance between two opposite sides(H): A = B x H

Answer 5

Area = 1/2 * diagonal1 * diagonal2

Answer 6

NO, the area in not 1/2 the product of diagonal
area = 1/2 diag1 x diag2 sin angle . . . for parallelogram
where angle is the acute angle between the two diagonal lines
Check it
diag1 = 10, diag2 =8, angle between them is 30 deg
area = 10(8)/2 sin 30 = 20

for a rhombus
Area = 1/2 diag^2 sin Angle
. . . . . . . . . . . where angle is the acute angle between diagonal
if the side is given
area = side^2 sin Beta
. . . . where Beta is the acute angle between the sides

Answer 7

1\2(d1*d2)=area of a rhombus

Answer 8

Check out this website...

http://www.mathsteacher.com.au/year8/ch12_area/05_rhombus/rhombus.htm

and I also found this formula...

A = ½ a× b
where a and b are the lengths of the diagonals

Answer 9

Let diagonals be of length d1 and d2
Area = (1/2) (d1 + d2)