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Show that sinθ = cosθ tanθ

2007-07-14 11:33:49 · 3 answers · asked by °†¿ÐámñéÐ?†° 2 in Science & Mathematics Mathematics

3 answers

Start with the right hand side:

(cos θ)(tan θ)

Change tangent to the ratio of sine to cosine.

cosθ [(sin θ) /(cos θ)]

The cosine divides out

sin θ

which is the left hand side!

2007-07-14 11:38:04 · answer #1 · answered by suesysgoddess 6 · 0 0

sinθ = cosθ tanθ

sinθ = cosθ (sinθ/cosθ)

cosθ cancels.

sinθ = sinθ

2007-07-14 18:38:20 · answer #2 · answered by Robert L 7 · 0 0

Let ABC be a triangle with a right-angle at B.

Then from the deifinitions of the ratios:
sin(A) = CB / AC
cos(A) = AB / AC
tan(A) = CB / AB

cos(A)tan(A)
= (AB/AC) * (CB/AB)
= CB / AC
= sin(A).

2007-07-14 19:12:18 · answer #3 · answered by Anonymous · 0 0

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