Solve the problem.
To get a C in history, Nandan must average 70 on four tests. Scores on the first three tests were 69, 79, and 60. What is the lowest score that Nandan can get on the last test and still receive a C?
70
72
69
2
2007-07-14 10:36:45 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Total required = 4 x 70 = 280
Sum of three tests = 69 + 79 + 60 = 208
Must score 72 in final test.
2007-07-15 07:24:04 · answer #1 · answered by Como 7 · 0⤊ 0⤋
(69 + 79 + 60 + x)/4 = 70
(208 + x)/4 = 70
52 + 1/4x = 70
1/4x = 18
x = 72
So he has to score at least 72 on his last test.
2007-07-14 17:42:34 · answer #2 · answered by Tsumego 5 · 0⤊ 0⤋
70 = (69 + 79 + 60 + x) / 4
70 - 52 = x/4
x = 72
he should get 72.
2007-07-14 17:41:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
72
2007-07-14 17:53:26 · answer #4 · answered by John M 7 · 0⤊ 0⤋
72
2007-07-14 17:46:39 · answer #5 · answered by hardlyworkin 1 · 0⤊ 0⤋
72
2007-07-14 17:44:44 · answer #6 · answered by Jesse A 1 · 0⤊ 0⤋
69
2007-07-14 17:47:22 · answer #7 · answered by MensaMan 5 · 0⤊ 0⤋
70*4=280.
First 3 scores add to 208.
If last score is 72, sum will equal 280.
2007-07-14 17:40:08 · answer #8 · answered by fcas80 7 · 0⤊ 0⤋