A person travels up a path at 8 in the morning from his car and arrives there at the destination at 4pm. Once there, the person decides that he doesn't like the location of the cabin and decides to return back to his car the following day. He leaves at 8am and gets back to his car at 2pm. Is there a place along his route that he passes through at the exact same time between the day before and the day after? ..question relates to continuous functions.
2007-07-14 10:31:35 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The person travels at the rate of D = 8t going up, where D is distance from the starting point and t is hours. t = D/8
He travels at the rate of t = D/6 going down.
Going up, he travels D/8 each hour and starts at point 0
Going down, he travel D/6 each hour and starts at point D.
D/8 * t = D - D/6 * t
Dt/8 = D - Dt/6
6Dt = 48D - 8Dt
6t = 48 - 8t
14t = 48
3 3/7 hrs = t
At 8am plus 3 3/7 hrs
to the nearest second, the time is 11:25:43 am
It's not calculus.
2007-07-14 11:27:42 · answer #1 · answered by Steve A 7 · 0⤊ 0⤋