[ |b+c| - (b+c) ] divided by [- |a-b| ]
a= -9
b= -6
c= -3
I got -6. Help?
2007-07-14 06:49:44 · 7 answers · asked by Sammy 2 in Science & Mathematics ➔ Mathematics
| b + c | = |- 6 - 3 | = | - 9 | = 9
b + c = - 9
|a - b| = |- 9 + 6| = | - 3 | = 3
b + c = - 6 - 3 = - 9
Let A = given expression.
A = [ 9 - (- 9) ] / (- 3)
A = 18 / (- 3)
A = - 6
2007-07-16 07:31:30 · answer #1 · answered by Como 7 · 0⤊ 0⤋
[ |- 6 - 3| - (- 6 - 3) ] divided by [ - | - 9 + 6 | ] =
[| - 9 | - ( - 9)] / [ - | - 3 |] =
[ 9 + 9] / [ 3 ] = 18/- 3 = - 6
2007-07-14 14:05:08 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
i get -6 also
2007-07-14 13:57:58 · answer #3 · answered by Erica C 2 · 0⤊ 0⤋
yes ur right good job u get a pat on the back
2007-07-14 14:05:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
[mod(b+c)]-(b+c)/[-mod(a-b)]
=[mod-9+9]/[-mod(-3)]
=[9+9]/[-3]
=18/-3=-6 ANS
your answer is correct.
2007-07-14 14:45:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
YOU ARE RIGHT 100%
2007-07-14 13:59:30 · answer #6 · answered by MAHAANIM07 4 · 0⤊ 0⤋
yea no doubt about it ur answer is right
2007-07-14 14:01:30 · answer #7 · answered by ninofire4 1 · 0⤊ 0⤋