2007-07-14 01:58:30 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
No, it isn't...
(-3a)² = (-3)² * a² = 9 * a² = 9a²
The square of a negative number is always positive.
2007-07-14 02:05:45 · answer #1 · answered by Anonymous · 2⤊ 0⤋
It is wrong because negative multiply by negative equal positive not negative anymore. It is quite a common mistake in algebra solving. E.g (-2) x (-2) = 2 NOT -2.
Therefore, the right answer should be:
(-3a)^2 = 9a^2
2007-07-14 10:07:38 · answer #2 · answered by <the unknown> 2 · 0⤊ 0⤋
Not,
(-1)^2 = (-1) x (-1) =1
(-3)^2 = (-3) x (-3) = (-1) x (-1) x (3) x (3) = 1 x 3 = 9
(-3a)^2 = (-3a) x (-3a) = (-1) x (-1) x (3) x(3) x (a) x (a) = 9a^2
2007-07-14 09:07:23 · answer #3 · answered by aspx 4 · 1⤊ 0⤋
No. Everything inside the parenthesis is subject to the exponent, so you have ((-)^2)(3^2)(a^2). (-)(-) = +, (3)(3) = 9, (a)(a) = a^2. If the negative sign was on the outside of the parenthesis it would be -9a^2, because the negative sign would not be subject to the exponent.
2007-07-14 09:14:49 · answer #4 · answered by gravelstatic 1 · 1⤊ 0⤋
No. You are confusing the expressions:
(-3a)^2 = 9a^2
and
-(3a)^2 = -9a^2
I think.
2007-07-14 09:37:25 · answer #5 · answered by Runa 7 · 0⤊ 0⤋
(-3a)^2 & -9a^2
If we divide both numbers with 3 then
-a^2 = -3a^2
If we divide both numbers with a^2 then
-1 = -3
Therefore, they are not equal.
2007-07-18 08:15:28 · answer #6 · answered by Jun Agruda 7 · 2⤊ 0⤋
(- 3 a)²
= (-3 a) x (-3 a)
= (- 3) x (- 3) x a x a
= 9 a²
2007-07-16 05:16:58 · answer #7 · answered by Como 7 · 0⤊ 0⤋
1)A negative times a negative is a positive...2)You add the exponents
2007-07-14 09:11:40 · answer #8 · answered by DJ BANDIT 1 · 1⤊ 0⤋
false
because a square can never be negative
2007-07-14 09:13:49 · answer #9 · answered by Anonymous · 1⤊ 0⤋