How many CFMs of air are required t cool an 80 C object to 60 C?

Question

I have an object which is 80 degrees centigrade, with the ambient air around it being 26.667 degrees centigrade, the air will be blown directly on the object at a tempureture of 21.111 degrees centigrade. Does anyone know approx. how many CFMs pumped in at those tempatures will be required to cool the 80 degrees centigrade down to approx. 60 degrees centigrade? Or does someone have a formula to figure it out? If you have a formula that is correct or gives a close aproximate but needs more info. I can fill in anything else just provide the formula please.

The mass of the object is 6489 grams and the surface area the air would be touching is 10 in. x 4 in. if that is important. Also what do you mean by heat cpacaity?

Answer 1

We need to know the thermal resistance (center-of-mass to ambient) of the object; Theta-cma [in degrees C per Watt]. You need to find or calculate that information. For semiconductors this value is always given (except for very low-powered stuff) as Theta, junction-to-ambient.

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Answer 2

You omitted the key input -> what is the mass of the object you are trying to lower the temperature of?

A whale takes more energy to chill than a canary.

Answer 3

kw = (334*10^(-6)) * (CFM) * (temp drop in F)

above is derived from basic heat storage equation:
q = (mass) * (specific heat) * (temp change)

we memorize the formula as energy equals to m*s*delta temp

Answer 4

there is a simple formula which is heat gained= heat lossed.

general formula used is MCO=MCO
m=mass
c= specific heat capacity
and 0= rise or fall in temp ( difference between initial and final temp)

Answer 5

to figure this out you are also going to need the R value of the object
The time would be different for instants if it was wood or rock glass or rubber