Take one guard and one inmate first.
Leave the inmate on the other side, return with the guard.
Take another inmate, return to the other side, leave the guard with the previous inmate.
Return with the inmate and take a guard. Leave the guard on the other side (there are now two guards on one side, with one inmate, one guard and one inmate on the first side, and one inmate in the boat)
Take one guard with the inmate on the boat and leave the inmate on the other side. There are now two inmates and two guards on the other side, with one guard on the boat and one inmate on the first side.
Go back with the guard and take the last inmate. Take both to the other side.
Done.
2007-07-11 18:38:48
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answer #1
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answered by JessC 2
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1. 1 Inmate and 1 Guard cross the river.
2. The inmate is dropped off and the Guard comes back.
3. 1 Guard is picked up and crosses the river with the inmate.
4. The guard is dropped off.
5. The inmate goes back.
6. 1 Guard is picked up and crosses the river with the inmate.
7. The guard is dropped off.
8. The inmate goes back.
9. 1 Guard is picked up and crosses the river with the inmate.
10. The inmate is dropped off.
11. The guard goes back.
12. The last inmate is picked up.
13. The guard and inmate cross the river and disembark.
Don't ask me what is to stop inmates from running off when there are no guards.
2007-07-11 18:40:30
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answer #2
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answered by Michael M 6
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you have two guards in one boat and have one stay across the land then have the other guard go back and have two inmates go and one stays then have the inmate go back and send the only guard across to the new land and have a inmate go back and pick up the other inmate that was left behind! now you r worried about the boats what happens when they are all lest together on the same land? Am i right pick me as best answer if i am!
2007-07-11 18:30:15
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answer #3
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answered by Anonymous
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THERE IS AN ISSUE WITH THIS RIDDLE OR THE ANSWER IS WRONG. When you bring the last guard back to the side with 2 inmates left, you have 1 guard and 2 inmates. The guard dies. Either there is an issue with the answer or the riddle sucks. See, when it comes to these "technical" riddles, the answers do not allow for such fallacies as the one I am pointing out. The solution of having the guard come back to the side that has 2 inmates would ALWAYS be a wrong answer. If it is the right answer, then this is not really a tough riddle. It is not really even much of a riddle.
ANSWER: GO LOOK FOR BETTER RIDDLES.
2015-09-05 03:04:00
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answer #4
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answered by Daniel 1
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Put one inmate with one guard in each boat.
There are three boats.
2007-07-11 18:29:53
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answer #5
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answered by Anonymous
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how many two seat boats do you have? If you have three then one guard and one inmate per boat.
2007-07-11 18:29:59
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answer #6
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answered by Anonymous
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2 GUARDS AND 1 INMATE IN EACH BOAT
2007-07-11 18:51:10
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answer #7
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answered by Anonymous
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have the guards make the inmates play rock paper BANG!
and cap the person that loses. until theres only one left.
problem solved. =)
2007-07-11 18:29:29
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answer #8
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answered by poets_loss 3
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G = Guard; I = Inmate, * = Boat
Start (GGGIII* - )
G + I goes over (GGII - GI*)
G comes back (GGGII* - I)
G + I goes over (GGI - GII*)
I comes back (GGII* - GI)
G + I goes over (GI - GGII*)
I comes back (GII* - GGI)
G + I goes over (I - GGGII*)
G comes back (GI* - GGII)
G + I goes over ( - GGGIII*)
Done!
This solution has a few occurances of GII but I can't find any other way to do it.
2007-07-11 18:47:36
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answer #9
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answered by Anonymous
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Let the prisoners drown???
2007-07-11 18:27:56
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answer #10
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answered by Anonymous
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