2007-07-08 12:53:57 · 6 answers · asked by Anonymous in Business & Finance ➔ Careers & Employment ➔ Other - Careers & Employment
It depends on how many loads they take where the loads are needed. As for the Ice Road Trucker documentary show. I have averaged about $750 per load. Another factor is how heavy the load is too I believe. Also if you have a fleet of trucks like Hugh on the show does, you would make really well. About $75,000 or so!!!
2007-07-09 04:09:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Ice Road Truckers Salary
2016-09-28 01:12:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This Site Might Help You.
RE:
What is the pay for an ice road trucker in Canada?
2015-08-10 18:46:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You must have been watching TV: but, didn't listen. A good man can make about $5000.00 a week.
That's for ten weeks. Some make more, some less. My grandson in Iraq, after the service went back to Iraq as an electrician and makes $15,000.00 per month.
A crab fisherman on the North sea makes about $30,000.00 for a ten weeks season but, if continues to go into other seasons can make a lot more.
When are you going to start, all are highly dangerous jobs that have a high death rate.
2007-07-08 13:07:19 · answer #4 · answered by cowboydoc 7 · 0⤊ 0⤋
are they in canada or alaska? sorry can't remember. He said he didn't have health insurance. I'm glad to see there's another person staying up late to watch a bunch of truck drivers drive across ice. Who says you have to be HOTT to draw an audience. :) Or maybe he's not Canadian...I don't think some of those guys are. Who knows! I'm just glad that it wasn't something more serious that an inflammed muscle whatever.. I didn't get the part where he said "I'm lucky to be here." Hmm?? I didn't realize that it was that serious of an injury. Did I miss something?
2016-03-20 04:02:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
around 75000 a year. thats what they said on there show.
2007-07-08 13:02:05 · answer #6 · answered by chevytrk1232000@yahoo.com 4 · 0⤊ 0⤋