So everyone knows that the formula of the point-slope form is (Y-Y1)=m(X-X1) in which that (m) is your slope, and (x,y) is your point. What do you do when your slope is a fraction?
Here's an example...
(2,6), m -2/3
Can anyone help? I'm good at math, but terrible at fractions....
2007-07-01 23:52:41 · 5 answers · asked by lilcreator 1 in Science & Mathematics ➔ Mathematics
[y-6] =-2/3[x-2]
=) 3[y-6] = -2[x-2]
=) 3y -18 = -2x+4
=)2x+3y-22=0
2007-07-02 00:00:04 · answer #1 · answered by rickey p 4 · 0⤊ 0⤋
How can you be good at math and be terrible at fractions? Fractions are part of the maths!
slope is m = - 2/3
So, we write y = mx + c and
We have a point with x = 2 and y = 6
So, 6 = -2/3 x 2 + c (that x is the multiplier, not x coordinate)
6 x 3 = -4 + 3c
3c = 18 + 4 = 22
c = 22/3
So, our equation is
y = - 2x / 3 + 22/3
or 3y = -2x + 22
2007-07-02 07:10:56 · answer #2 · answered by Swamy 7 · 0⤊ 1⤋
if the slope is a fraction . . .
then solve first the common denominator
then cross multiply
y = - 2/3 x + 6. . . . this is actually the equation of a line
2007-07-02 07:03:41 · answer #3 · answered by CPUcate 6 · 0⤊ 1⤋
You're looking at an equation of the form
y = -2/3 x + b
Just plug in the numbers
6 = -(2/3) * 2 + b
6 = -(4/3) + b
6 + (4/3) = b
7 1/3 = b
The equation is thus y = -(2/3) * x + 7 1/3.
2007-07-02 07:00:25 · answer #4 · answered by Anonymous · 0⤊ 1⤋
it would just be (Y-6)=-2/3(X-2)
2007-07-02 07:00:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋