Average V=(V1+V2)/2 = (10m/s +30m/s)/2 = 20 m/s
Acceleration = (V2-V1)/t = (30m/s - 10m/s) / 20s = 1 m/s^2
Dist = (V1+V2)/2 * t = (10m/s + 30m/s)/2 * 20s = 400 m
2007-07-02 01:40:21
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answer #1
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answered by Ernst S 5
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Oh for heaven's sake! Have you even tried applying your brain to this question before blindly posting it here hoping someone will help you cheat on your homework? All the information you need to answer that question is in the question, and the whole point of having these questions is so you learn how to do them.
You have the speed at the beginning and the speed at the end, so you can work out the average of those speeds. You have the difference in velocity, and you have the time period over which this change took place, which tells you the acceleration. You worked out the average speed earlier, and you have the time period, so you can work out the distance. Go do it.
2007-07-02 06:36:01
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answer #2
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answered by Jason T 7
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accelleration: 1 m/s (30-10 = 20 / 20 (sec))
average speed 20 m/s (30 + 10 / 2)
distance: 20 meters (1 meter per second accelleration multiplied by 20 seconds in time...)
you should really figure this out yourself, it's quite easy...
2007-07-02 19:31:53
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answer #3
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answered by mcdonaldcj 6
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Your " Space Truckin' " huh? ... dis is the Astronomy & Space World ...kapeesh? not the drag strip! But hey, its Vegas Baby! 100 to 1 odds my truck will beat your truck in the "quarter lite-year"!
Takers?
2007-07-02 06:33:00
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answer #4
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answered by HitMan Harry 3
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Average V=(V1+V2)/2 = 20 m/s
Acceleration = (V2-V1)/t = 1 m/s^2
Dist = (V1+V2)*t/2 = 200 m
2007-07-02 08:09:55
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answer #5
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answered by Anonymous
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Average V=(V1+V2)/2 = 20 m/s
Acceleration = (V2-V1)/t = 1 m/s^2
Dist = (V1+V2)*t/2 = 200 m
2007-07-02 06:33:32
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answer #6
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answered by i_am_here_now2 1
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This is ASTRONOMY & SPACE.
It is not the MY HOMEWORK section.
You and your lazy brain are headed for a great job as "Hamburger Flipper" at Mickey D's. And you deserve it.
2007-07-02 09:09:18
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answer #7
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answered by Anonymous
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avg sp.== 20m/s , acc.->1m/s^2
2007-07-02 07:01:41
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answer #8
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answered by bua 1
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