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consider the points a=(-1,2),b=(6,4) and c=(1,-20) in the plane.For how many different points d in the plane are a,b,c,d are the vertices of a parallelogram

2007-07-01 20:41:10 · 3 answers · asked by Anuj S 1 in Science & Mathematics Mathematics

3 answers

3

The points are found opposite the sides of the triangle abc.

To further, if the new points are formed into a bigger triangle the points a,b&c are the midpoints of each side.

2007-07-01 20:47:15 · answer #1 · answered by Alam Ko Iyan 7 · 0 0

yeah 3 is right
Do u know this rule
For a b c d pts forming a parallelogram in that order
ax + cx = bx + dx
ay + cy = by + dy

So, using different arrangements of pts,u will get three possibilites

Say
abcd ..b is opposite to d

bacd........a is opposite to d

bcad ....... c is opposite to d

In first case, using rule stated,
-1 + 1 = 6 + dx
we get dx = -6

2 - 20 = 4 + dy
dy= -22

so d is ( -6,-22)

In this manner u can find 2 other possible points..........

2007-07-01 20:55:18 · answer #2 · answered by amudwar 3 · 0 0

There will be three points in the plane, one in the first quadrant, one in the second and one in the third quadrant for which we can have a parallelogram.

2007-07-01 20:51:02 · answer #3 · answered by Swamy 7 · 0 0

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