Me and my friend came out with the answer of pt-slope form = y+7=-2/5x and standard form=2x+5y=-35. My teacher said the way we got the answer was wrong. How would you work this out?
2007-07-01 20:04:38 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
ur answer is correct. this is the right procedure:
Find equation of line passing through pt (0,-7) with slope= -2/5 in pt slope AND standard forms.?
y=mx+b
-7= -2/5(0) +b
-7=b
pt. slope
y= -2/5x -7
then in standard form:
2/5x+y=-7 or
2x+5y= -35
2007-07-01 20:16:41 · answer #1 · answered by kent 2 · 0⤊ 0⤋
The correct way to find the equation is:-
The equation passing through a point (x',y') and having slope m is given by (y-y')=m(x-x')
So you get equation [y-(-7)]= -2/5[x-0]
or y+7= -2/5x
or simplified to give 2x+5y+35=0
2007-07-01 20:35:58 · answer #2 · answered by Indian Primrose 6 · 0⤊ 0⤋
There seems to be something missing here. You said your teacher said the way you got the answer was wrong. The answers are correct. How did you get your answers?
2007-07-01 20:26:56 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋