so you have two numbers x and y
x = y-8 (one number is 8 less than another)
xy = 345 (product of the two numbers is 345)
now substitute in y-8 for x into the second equation
(y-8)y = 345
y^2 -8y -345 = 0 using the quadratic formula
y = (-b +/- sqrt(b^2-4ac)/(2a) where a = 1, b = -8, c = -345
y = (8 +/- sqrt((-8)^2 -4*1*(-345))/(2*1)
= (8 +/- sqrt(64+1380))/2
= (8 +/- sqrt(1444))/2
= (8 +/- 38)/2
y = -15 or 23
if y = -15 then x = (y-8) = (-15-8) = -23
if y = 23 then x=y-8 = 23-8 = 15
verify answers
15*23 = 345
(-23)*(-15) = 345
so your answers are
15 and 23 AND
-15 and -23
There are two sets of answers because it wasn't specified that the numbers were positive or negative.
2007-07-01 19:04:30
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answer #1
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answered by Navidad_98 2
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Let the first number be n therefore the second number is n + 8. The product of n * (n + 8) = 345.
Solve for n
n*(n + 8) = 345
n^2 + 8n - 345 = 0
(n + 23)(n - 15)=0
n = -23 or n=15
so the two numbers are -23 and -15 or 15 and 23
Gotta assume that you are only looking for positive numbers so the answer would be 15 and 23.
2007-07-02 01:58:24
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answer #2
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answered by GeekCreole 4
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One number we'll call x. This number is 8 less than another number we'll call y.
So the equation would look like this.
x = y-8
And the product of those to numbers x and y is 345. Or
x * y = 345
So we know x = y-8 we can plug that into the equation above to get:
(y-8) * y = 345
Multiply through the y to get:
y^2 - 8y = 345
bring the 345 to the left side
y^2 - 8y - 345 = 0
Use the quadratic formula.
And get y = -15 and 23.
Plug that into the first equation to find x.
2007-07-02 02:00:45
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answer #3
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answered by A B 3
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1) x = y -8
2) xy=345
use direct substitution
plug equation 1 into equation 2
(y-8)(y)=345
distribute to get y^2-8y=345
subtract 345 from both sides
y^2 - 8y - 345 = 0
(y+15)(y-23)=0
y= -15, 23
plug the y value into the first equation
x = -15 - 8
x = -23
x=23-8
x=15
there are two sets of answers that work here (y= -15, x =-23 )
and (y = 23, x =15) Depending on the question, you figure out which is the correct one
2007-07-02 01:57:45
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answer #4
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answered by superman 4
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You need to make this word problem into a system of equations. You know two things, and can relate them. First, one number is 8 less than the other. So you know that one number minus 8 equals the other. For ease of use, let's call one number (the first number) "X" and the other number "Y". In mathematical symbology, you know that x-8=y.
You also know that the product of the two numbers is 345. So you know that x*y=345.
So you have two equations:
x-8=y
x*y=345
Now solve!
2007-07-02 01:54:58
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answer #5
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answered by veenteam 2
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numbers are x and x-8, so
x(x-8) = 345
x² - 8x = 345
x² - 8x + 16 = 345 + 16
(x - 4)² = 361
x - 4 = ±â361 = ±19
x = 4 + 19 = 23
x-8 = 15
or
x = 4 - 19 = -15
x-8 = -23
2007-07-02 01:55:45
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answer #6
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answered by Philo 7
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Let the number be x.
then second number is (x-8).
thus ,x*(x-8)=345
on solving this equation we get the two numbers as 23 & 15,.
2007-07-02 01:56:44
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answer #7
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answered by vikes 1
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let the number be x and (x-8)
x (x-8) = 345
x^2 - 8x - 345 = 0
use quadratic equation and solve for x
2007-07-02 01:54:27
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answer #8
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answered by Sam 3
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x(x-8)=345
x^2 -8x=345
x^2-8x-345=0
x^2+15x-23x-345=0
x(x+15) -23(x+15)=0
(x+15)(x-23)=0
so x= 23
one number is 23
and the other is 23-8= 15
2007-07-02 01:54:07
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answer #9
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answered by sweet n simple 5
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