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one number is eight less than another. the product of the two numbers is 345. what are the two numbers?

Show steps please. Ty!

2007-07-01 18:50:32 · 9 answers · asked by I'm B O R E D 2 in Science & Mathematics Mathematics

ty everybody. But it happens that juzz doing random numbers helped me get the answer rofl thanks tho

2007-07-01 18:59:35 · update #1

9 answers

so you have two numbers x and y

x = y-8 (one number is 8 less than another)
xy = 345 (product of the two numbers is 345)

now substitute in y-8 for x into the second equation

(y-8)y = 345
y^2 -8y -345 = 0 using the quadratic formula

y = (-b +/- sqrt(b^2-4ac)/(2a) where a = 1, b = -8, c = -345

y = (8 +/- sqrt((-8)^2 -4*1*(-345))/(2*1)
= (8 +/- sqrt(64+1380))/2
= (8 +/- sqrt(1444))/2
= (8 +/- 38)/2

y = -15 or 23

if y = -15 then x = (y-8) = (-15-8) = -23
if y = 23 then x=y-8 = 23-8 = 15

verify answers

15*23 = 345
(-23)*(-15) = 345

so your answers are

15 and 23 AND
-15 and -23

There are two sets of answers because it wasn't specified that the numbers were positive or negative.

2007-07-01 19:04:30 · answer #1 · answered by Navidad_98 2 · 1 0

Let the first number be n therefore the second number is n + 8. The product of n * (n + 8) = 345.

Solve for n

n*(n + 8) = 345
n^2 + 8n - 345 = 0
(n + 23)(n - 15)=0
n = -23 or n=15
so the two numbers are -23 and -15 or 15 and 23

Gotta assume that you are only looking for positive numbers so the answer would be 15 and 23.

2007-07-02 01:58:24 · answer #2 · answered by GeekCreole 4 · 0 0

One number we'll call x. This number is 8 less than another number we'll call y.

So the equation would look like this.

x = y-8

And the product of those to numbers x and y is 345. Or

x * y = 345

So we know x = y-8 we can plug that into the equation above to get:

(y-8) * y = 345

Multiply through the y to get:

y^2 - 8y = 345

bring the 345 to the left side

y^2 - 8y - 345 = 0

Use the quadratic formula.

And get y = -15 and 23.

Plug that into the first equation to find x.

2007-07-02 02:00:45 · answer #3 · answered by A B 3 · 0 1

1) x = y -8

2) xy=345

use direct substitution
plug equation 1 into equation 2

(y-8)(y)=345
distribute to get y^2-8y=345
subtract 345 from both sides
y^2 - 8y - 345 = 0
(y+15)(y-23)=0
y= -15, 23

plug the y value into the first equation
x = -15 - 8
x = -23

x=23-8
x=15
there are two sets of answers that work here (y= -15, x =-23 )
and (y = 23, x =15) Depending on the question, you figure out which is the correct one

2007-07-02 01:57:45 · answer #4 · answered by superman 4 · 0 0

You need to make this word problem into a system of equations. You know two things, and can relate them. First, one number is 8 less than the other. So you know that one number minus 8 equals the other. For ease of use, let's call one number (the first number) "X" and the other number "Y". In mathematical symbology, you know that x-8=y.

You also know that the product of the two numbers is 345. So you know that x*y=345.

So you have two equations:
x-8=y
x*y=345

Now solve!

2007-07-02 01:54:58 · answer #5 · answered by veenteam 2 · 0 0

numbers are x and x-8, so
x(x-8) = 345
x² - 8x = 345
x² - 8x + 16 = 345 + 16
(x - 4)² = 361
x - 4 = ±√361 = ±19
x = 4 + 19 = 23
x-8 = 15
or
x = 4 - 19 = -15
x-8 = -23

2007-07-02 01:55:45 · answer #6 · answered by Philo 7 · 1 0

Let the number be x.
then second number is (x-8).
thus ,x*(x-8)=345
on solving this equation we get the two numbers as 23 & 15,.

2007-07-02 01:56:44 · answer #7 · answered by vikes 1 · 0 0

let the number be x and (x-8)
x (x-8) = 345
x^2 - 8x - 345 = 0

use quadratic equation and solve for x

2007-07-02 01:54:27 · answer #8 · answered by Sam 3 · 1 0

x(x-8)=345
x^2 -8x=345
x^2-8x-345=0
x^2+15x-23x-345=0
x(x+15) -23(x+15)=0
(x+15)(x-23)=0

so x= 23

one number is 23
and the other is 23-8= 15

2007-07-02 01:54:07 · answer #9 · answered by sweet n simple 5 · 1 0

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