2007-07-01 16:37:17 · 10 answers · asked by J 6 in Science & Mathematics ➔ Mathematics
This is an arithmetic series
S = n/2 (t[1] + t[n])
n: Number of terms
t[1]: First term
t[n]: Last term
Number of terms = 9999-666+1 = 9334
S = 9334 * (666 + 9999) / 2
= 49,773,555
2007-07-01 16:41:21 · answer #1 · answered by gudspeling 7 · 3⤊ 0⤋
The sum from 1 to n is given by n*(n+1)/2
Calculate the sum from 1 to 9999 and subtract the sum from 1 to 665.
Sum = 9999*10000/2 - 665*666/2
Sum = 49,773,555
2007-07-01 23:43:45 · answer #2 · answered by GeekCreole 4 · 2⤊ 0⤋
use the formula n(n+1)/2
eg 1 + 2 + 3 + 4 + 5 = 15
n = 5
5(5+1)/2 = 5*6/2 = 15
find the sum from 1 to 665
then find the sum from 1 to 9999
get the difference and you got your value
2007-07-01 23:45:53 · answer #3 · answered by Sam 3 · 2⤊ 0⤋
9999*10000/2 - 665*666/2 =
49,773,555
2007-07-01 23:44:33 · answer #4 · answered by Helmut 7 · 1⤊ 1⤋
S, sum of an arithmetic series
S = n(F + L) / 2
where
n = number of terms
F = first term
L = last term
S = (9,999 - 666 + 1)(666 + 9,999) / 2
S = 9,334(10,665) / 2
S = 49,773,555
2007-07-01 23:42:03 · answer #5 · answered by mathjoe 3 · 2⤊ 0⤋
Finding solutions to such problems are very easy !
I am giving you a permanent solution.
I suggest you to just visit http://www.gojocal.org
Download the free mathematical series software. It can do all similar calculations easily for you !
All the best !
2007-07-02 04:48:04 · answer #6 · answered by Anonymous · 1⤊ 1⤋
You lost me when you said "sum".....I guess these other answers are right.
2007-07-02 00:00:56 · answer #7 · answered by chilicooker_mkb 5 · 1⤊ 0⤋
Well, you can't really count it out. Isn't there a formula?
2007-07-01 23:43:58 · answer #8 · answered by Anonymous · 0⤊ 1⤋
sum? hmmm
2007-07-01 23:41:52 · answer #9 · answered by Anonymous · 2⤊ 2⤋
49773555
2007-07-02 00:04:37 · answer #10 · answered by Anonymous · 2⤊ 0⤋