log(x) + log(2x) = 10
2007-07-01 14:20:34 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First, get the same log base on both sides. We already are working with log base 10, so put that on the right side:
log(x) +log(2x) = Log(base 10)10^10
The right side cancels out to 10, so it's still the same.
Then we use a basic rule of logs and just cross out all those logs. Now we have:
x + 2x = 10 Solve for x
2007-07-01 14:26:21 · answer #1 · answered by gangreless 2 · 0⤊ 0⤋
I think you are supposed to multiply the bases (x) and (2x) together, then solve them for x if the equation log(x)+log(2x)=10. I can't remember... x= (+-)5^(1/2)?
Or do you mean log base 10 for both logarithms? I don't know... sorry.
2007-07-01 21:32:29 · answer #2 · answered by Another lazy kid 3 · 0⤊ 0⤋
log(x) + log(2x) is the same as log(2x^2) according to Log Property: log(A) + log(B) = log(AB)
log(2x^2) = 10, then change that to an exponential equation
2x^2 = 10^10 = 10000000000 -Divide that by 2.
x^2 = 5000000000
x = 70710.68 (Rounded to nearest tenth)
2007-07-01 21:31:46 · answer #3 · answered by Kumori 4 · 0⤊ 0⤋
log (2x²) = 10
2x² = 10^10
x² = 10^10 / 2
x = 70711 ( to nearest whole number)
2007-07-05 17:43:58 · answer #4 · answered by Como 7 · 0⤊ 0⤋