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2t^4x^4 -32x^4

2007-07-01 14:08:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Remember that a^2 - b^2 = (a+b)(a-b)

2x^4 is common:

2x^4(t^4 - 16)
= 2x^4((t^2)^2 - 4^2))
= 2x^4(t^2 + 4)(t^2 - 4)
= 2x^4(t^2 + 4)(t^2 - 2^2)
= 2x^4(t^2 + 4)(t + 2)(t - 2)
= 2x^4(t+2)(t-2)(t^2+4)

2007-07-01 14:12:49 · answer #1 · answered by gudspeling 7 · 0 0

2t^4x^4 -32x^4

2x^4 (t^4 - 16)

2x^4 (t² - 4)(t² + 4)

2x^4 (t + 2)(t - 2)(t² + 4)
.

2007-07-01 21:15:40 · answer #2 · answered by Robert L 7 · 0 0

2x^4(t^4-16)
2x^4(t^2-4)(t^2+4)
2x^4(t-2)(t+2)(t^2+4)

2007-07-01 21:12:43 · answer #3 · answered by Anonymous · 0 0

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