hey guys~ i am having trouble with a physics problem.
An ion's position vector is initially r = 8.0 i - 5.0 j, and 8.0 s later it is r = 5.0 i + 3.0 j, all in meters. What was its vavg during the 8.0 s?
I calculated the change in velocity and got the answer for j, but not for i. I don't understand why I can't get i right.
any suggestions?
thank you!
2007-07-01 14:05:27 · 3 answers · asked by kyla 1 in Science & Mathematics ➔ Physics
(5.0i + 3.0j) - (8.0i - 5.0j) = -3.0i + 8.0j; Divide by 8 sec
-.375i + j
|v| = 1.068
2007-07-01 14:41:25 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
all vectors >>
average velocity = delta r/delta t = [r(final) - r (initial)] /delta t
v (avg) = [5.0 i + 3.0 j - 8.0 i + 5.0 j] / 8
v (avg) = [ - 3.0 i + 8.0 j ] / 8
v (avg) = - (3/8) i + j
|v(avg)| = sqrt [ (3/8)^2 + 1] = 1.068 m/s
direction tan (p) = 1/(- 3/8) =
p = angle = 69.44 degree east of south (4th quardant or 360 - 69.44)
2007-07-01 14:41:19 · answer #2 · answered by anil bakshi 7 · 0⤊ 0⤋
1. I fink it is -3/8i + j m/s
2007-07-01 14:30:56 · answer #3 · answered by Gaz T 5 · 0⤊ 0⤋