Vol = pi r^2 h
r=9
h=54/12=4.5
volume = 1145.6 cu ft
1145.6 x 7.481= 8570 gallons
(1 cubic foot = 7.481 gallons)
2007-07-01 11:39:18
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answer #1
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answered by skipper 7
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Assume a circular pool of diameter 18 ft
V = Ï x 9² x 4.5 ft ³
V = 1145 ft ³
But 1 ft³ = 7.5 gallons
V = 1145 x 7.5 gallons
V = 8588 gallons
2007-07-05 10:18:41
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answer #2
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answered by Como 7
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If you have a graphing calculator, you can do all similar conversion problems faster.
You go: APPS->SciTools->Enter->Unit Conversion->Volume
volume
= pi (9^2)(54/12) ft^3
= pi (9^2)(54/12) ft^3 (1 gal /0.133681 ft^3)
= 8566.0 gal
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Don't do round off until the last step.
2007-07-01 12:01:11
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answer #3
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answered by sahsjing 7
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I believe your question states 18ft rnd (Circumference) ?
Diameter = Circumference ÷ Pi
= 18 ÷ 3.14 = 5.73ft
Radius = 5.73 ÷ 2 = 2.87 ft.
Depth = 54" = 4.5'
Volume = Ï x r x r x h (depth) = 3.14 x 2.87 x 2.87 x 4.5
= 116 ft³.
1 ft³ = 7.5 US gallons...116 x 7.5 = 872 US gallons.
2007-07-01 12:56:06
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answer #4
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answered by Norrie 7
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That's what I'm wondering, just done it and dreading the water bill! I just checked mine on intexcorp.com. It holds 5894 gallons!
2007-07-01 11:34:07
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answer #5
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answered by Anonymous
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