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Find the domain: f(x)= 3/x+1

a. (-infinite,-3)
b. (-infinite,-1)U(-1,infinite)
c. (-infinite,-3)U(-3,infinite)
d. (-infinite,-1)

2007-07-01 05:30:24 · 5 answers · asked by how's it going 1 in Science & Mathematics Mathematics

5 answers

The answer is B, assuming you meant 3/(x+1).

The only restriction is on the denominator, in that it cannot be equal to 0 due to the division by zero property.

x+1=0 when x = -1. Therefore x is not equal to -1 but could be anything else.

2007-07-01 05:37:05 · answer #1 · answered by whitesox09 7 · 0 0

x can be any value except 0, except if you meant:
f(x) = 3/(x+1). If this is what you meant, the x can take on any value except -1. In this case the answer would be b (-infinite,-1)U(-1,infinite).

2007-07-01 12:44:44 · answer #2 · answered by ironduke8159 7 · 0 0

if you meant f(x) = 3/x + 1:
the function f(x) is not defined for x = 0, so a correct domain would be one not containing 0, so A and D are correct

if you meant f(x) = 3/(x+1) then the function is not defined for -1
so the correct answer is A,B or D because those domains don't contain x = -1

2007-07-01 12:38:14 · answer #3 · answered by djlaxa 2 · 0 0

You need some paranthesis to remove your ambiguity.

(3/x) + 1
or
3/(x+1)

are very different animals.

2007-07-01 12:49:37 · answer #4 · answered by none2perdy 4 · 0 0

b

2007-07-01 12:40:35 · answer #5 · answered by FifiLone 2 · 0 0

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