tHANK YOU
2007-07-01 05:16:14 · 7 answers · asked by JeususismyRock! 1 in Science & Mathematics ➔ Mathematics
an easy way to think of slope is rise/run or how far the line rises in y direction over how far it goes in the x direction
in your case
slope = (5-5)/(-5-(-3)) = 0 so there is no slope! If you think about it this makes sense as the line starts at the point where y=5 and finishes at a point where y=5, ie. a flat line with no slope
2007-07-01 05:37:54 · answer #1 · answered by theanswerman 3 · 0⤊ 0⤋
The slope of a line is called the gradient of the line.
You can use this gradient formula to find the slope of a line:
gradient of line = change in y/ change in x
= (Y2 -Y1)/(X2 - X1)
Solution:
Let point (-5, 5) be (X1, Y1) and point (-3, 5) be (X2, Y2)
Substituting the values into the formula,
gradient of line = (5 - 5)/[-3 -(-5)]
= 0/2
= 0
The line has zero gradient which means that this line
does not slope hence, it is a horizontal line passing the
y-axis at point (0, 5).
2007-07-01 12:56:41 · answer #2 · answered by amethyst 1 · 0⤊ 0⤋
If a line is drawn thro` given points, it will be horizontal.
ie gradient(slope) = 0
Proof
m = (5 - 5) / (- 3 + 5)
m = 0 / 2
m = 0
2007-07-05 03:13:02 · answer #3 · answered by Como 7 · 0⤊ 0⤋
slope= (difference in y-coordinate)(difference in x-coordinate)=(5-5)/(-3+5)=0/2=0.This is a simple and an easy question.
2007-07-01 12:41:53 · answer #4 · answered by kamaldhero 1 · 0⤊ 0⤋
slope is (5-5)/(-3+5) = 0
2007-07-01 12:20:00 · answer #5 · answered by Mock Turtle 6 · 1⤊ 0⤋
slope= (y1-y2)/(x1-x2)
=5-5/-5--3
=0/-2
=0
Next time: Just use the equation (y1-y2)/(x1-x2)
2007-07-01 14:12:12 · answer #6 · answered by CoolioMADDog 4 · 0⤊ 0⤋
in general the gradient is given by (change in y) divided by (Change in x)
dy/dx in posh calculus terms!
change in y is 0
change in x is 2
0/2 = 0
therefore gradient is zero.
2007-07-01 12:19:42 · answer #7 · answered by DAN H 3 · 1⤊ 0⤋