solve: x^2 + 5x = 7 (x squared +5x = 7)?

Answer 1

use quadratic formula for ax² + bx + c =0. a = 1.

it becomes x² +5x -7=0

Thus x = { -b ± √(b² - 4c) } / 2

Get the values of x. If the radicand is negative, the number is non-real, meaning complex number. i = √(-1).

Answer 2

First step with most polynomial equations is to get everything on one side of the equation and zero on the other, like so:

x^2 + 5x - 7 = 0

Then try to factor the left side. The left side in this instance won't factor, but it is a quadratic equation that can be solved by the least squares method or by the quadratic equation.

For an equation of the form

ax^2 + bx + c = 0, the solutions for x will be of the following form, where a ≠ 0:

x = (-b + sqrt (b^2 - 4ac)) / 2a

and

x = (-b - sqrt (b^2 - 4ac)) / 2a

This is the quadratic equation method. In this example, a = 1, b = 5, and c = -7.

The expression inside the square root, b^2 - 4ac, is known as the discriminant. If the coefficients a, b, and c are real numbers, there are three possible outcomes, depending on the discriminant:

If the discriminant is positive, as in this case, the equation has two real solutions.

If the discriminant is zero, the equation has two real solutions, one of which is redundant because it is the same as the other.

If the discriminant is negative, the equation has no real solution but a pair of conjugate complex solutions.

In this case, the discriminant is 5^2 - 4*1*(-7), or 53. The solutions are therefore

x = (-5 + sqrt(53)) / 2 and x = (-5 - sqrt(53)) / 2

Answer 3

Answer for your Quadratic Equation



Your Problem is 1 x2 +5 x +7 = 0
We can solve this problem by the following methods
Note : the multiplication sign is * here to avoid confusion with x

We can only use ABC formula for this problem
Reason : the Determinant value is negative, so
the result will involve imaginary number ( i = (-1)(1/2) )
The Determinant of Quadratic Equation is b2 - 4ac

1 x2 +5 x +7 = 0
We have to turn it into ax2 +b x + c = 0 form, so
a=1 , b=5 , c=7
Use the following formula :
x = (-b+(b2-4ac)(1/2))/2a OR x = (-b-(b2-4ac)(1/2))/2a, enter the value of a,b,c to this formula
x = (-5+( (5)2 - 4 * 1 * 7)(1/2))/(2 * 1) OR x = (-5-( (5)2 - 4 * 1 * 7)(1/2))/(2 * 1)
x = (-5+(-3)(1/2))/(2 * 1) OR x = (-5-(-3)(1/2))/(2 * 1)
x = (-5+(-3)(1/2))/2 OR x = (-5-(-3)(1/2))/2
x = (-5 + 1.73205080757 i )/2 OR x = (-5 - 1.73205080757 i )/2
x = -2.5 + 0.866025403784 i OR x = -2.5 - 0.866025403784 i

Answer 4

x² + 5x - 7 = 0
x = [- 5 ± √(25 + 28) ] / 2
x = [- 5 ± √(25 + 28) ] / 2
x = [- 5 ± √53 ] / 2
x = 1.14 , x = - 6.14

Answer 5

x^2+5x-7=0


-5+-sqrt(5^2-4*7)/2

since 25-28=-3 the answer is complex

-5+--3i/2

Answer 6

x^2+5x=7
x^2+5x-7=0
Using the quadratic formula

x=(-b+-sqrt(b^2-4ac))/2a

a=1, b=5,c=-7

x=(-5+-sqrt(5^2-4(1)(-7)))/2(1)
x=(-5+-sqrt(25+28))/2
x=(-5+-7.28)/2
therefore
x= -6.14 or x=1.14