the semicircle is placed on top of the rectangle at its center point on the 6 feet length.
There is no overlapping of the area. The total area is that of the rectangle and the semicircle.
2007-06-30 20:24:19 · 6 answers · asked by CPUcate 6 in Science & Mathematics ➔ Physics
the 6 ft length is horizontal, 4 ft is vertical
the semicircle is on top of the 6 ft on the top of rectangle at its center
2007-07-01 13:45:55 · update #1
centroid of semicircle = 4r/3/pi = 0.8488
A1 = 1/2 pi r^2 = 1/2 pi (2)^2 = 6.263
A2 = 6 (4) = 24
total area = 30.283
centroid from the bottom
30.283 y = 6.263 (4+0.8488) + 24(2)
y = 2.591
centroid (3, 2.591)
No one got it
2007-07-01 14:39:51 · update #2
No, thanks.
2007-06-30 20:28:00 · answer #1 · answered by Bill 1 · 0⤊ 0⤋
Centroid Of Semi Circle
2016-10-16 11:47:43 · answer #2 · answered by herne 4 · 0⤊ 0⤋
The centroid of the semicircle is at a distance of (4r/3Л) from the center of the circle
The centroid of the rectangle is at its center, ‘3” from the center of the circle.
Distance between the centroids = (4 *2 /3Л + 3) = 3.85 ft.
Area of semicircle is Л r^2 /2 = 6.28 ft^2.
Area of rectangle = 24 ft^2.
If x is the centroid of the combinations from the center of the rectangle,
6.28 (3.85 –x) = 24 x
30 .28 x = 24.178
x = 0.785 from the center of the rectangle toward the center of the circle.
If we keep the semicircle vertically above the rectangle, then the centroid is 3.785 ft from the bottom.
2007-06-30 23:15:20 · answer #3 · answered by Pearlsawme 7 · 0⤊ 0⤋
As = (π/2)2^2 = 2π ≈ 6.2832 ft^2
centroid at 3, 1.5708 ft above baseline
Ar = 24 ft^2
centroid at 3, 2
(6.2832*1.5708 - 2*24)/30.2832 + 4 = 2.7409
centroid of the composite is at 3, 2.74 from the bottom left corner of the rectangle.
2007-06-30 21:04:29 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
Ay(bar) = A1y1(BAR) + A2y2(BAR).....y(BAR) = total centroid
y1 for rectange and y2 for cemicircle...
y1(bar) = half of rectangle.....
y2(bar) = (find on google, can't remember)
A1 = area of rectangle
A2 = area of semicircle
A=total area
Then you divide both sides by the total area 'A' to find y(bar)
To find moment of inertia Use parralel axis theorem....
Use i1 i2..where i1 = the moment of inertia...for rectangle i = bh^3/12
2007-06-30 20:31:23 · answer #5 · answered by chaminda l 6 · 0⤊ 0⤋
get some fish from nemo wait it is marien right ?
2016-03-19 05:07:10 · answer #6 · answered by ? 4 · 0⤊ 0⤋