When answering this question please indicate a solution for both configurations (series and parallel) for inductors. Thanks.
2007-06-28 16:10:35 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Resistors and inductors use the same formula(s).
In series, they add just as you stated. In parallel, you combine the inverse values.
Series: R1+R2+R3= Rtotal
Series: L1+L2+L3=Ltotal
Parallel: 1/R1 + 1/R2 + 1/R3 = 1/Rtotal
Parallel: 1/L1 + 1/L2 + 1/L3 = 1/Ltotal
These formulas are good for any number of resistors or inductors in series or parallel.
A "shortcut" formula for resistors or inductors in parallel if there are just two of them is:
(R1*R2) / (R1+R2) = Rtotal
(L1*L2) / (L1+L2) = Ltotal
2007-06-28 16:21:07 · answer #1 · answered by TechnoStuff 4 · 0⤊ 0⤋
Inductors In Parallel
2016-11-14 05:24:11 · answer #2 · answered by dziabula 4 · 0⤊ 0⤋
Adding Inductors
2017-01-04 13:44:49 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Inductors are also similar to resistors and add in series. There are two components in inductors, the resistance and inductance. The resistance is negligible compared to inductance. But inductance comes into play only when an alternating current flows.
Inductance = L x2 pi x f where L= inductance, pi= 3.14 and f= frequency
2007-06-28 16:20:52 · answer #4 · answered by rajan l 6 · 0⤊ 0⤋
There is a difference between resistors and inductors. Mutual inductance. If 2 inductors are close together then there is a transformer like action which changes their effective value, mutual inductance is very hard to predict, and can be between inductors in two seperate circuits which can create noise and unexpected voltages.
2007-06-29 06:11:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Inductances in series add, like resistors. All of these are true as long as only one type of impedance is in the circuit. Inductances in parallel are combined like resistors in parallel:
1/Lt = 1/L1 + 1/L2
2007-06-28 16:14:12 · answer #6 · answered by gp4rts 7 · 1⤊ 0⤋
Inductance is simillar to resistance.
Inductance is propotional to (N*N*A)/l
N is number of turns of coil of inductance
A is area of cross section of inductance
l is length of the coil.
It comes out as [(Mu)N*N*A]/l
Mu being the permeability of free space
Now comming to the series and parallel combinations, u can easily say that the number of turns increase linearly with the remaining terms remaining constant.
so in series combination Total Inductance is sum of individaul inductances
L1+L2+L3
parallel combination of inductance 1/L1+1/L2+....
2007-06-28 16:32:05 · answer #7 · answered by Krishna D 2 · 0⤊ 0⤋