Why is it difficult to have a circuit with both high current and high voltage?
I can't think how this would occur or why they are hard to meet!
2007-06-27 04:12:13 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
In simple terms, voltage x current = power.
Volts x Amps = Watts
High Voltage x High Amperage = Very High Power.
The difficulty has to do with the fact that high voltage equipment needs a lot of insulation or separation to grounded equipment or other conductors.
Sustained high current needs conductors with a very large cross-sectional area. i.e. Really big wires!
Combining these two makes it very difficult to manufacture equipment to connect to the circuit. Generally the voltage is increased to allow smaller sized conductors.
This is where the electric utility comes in. A high voltage transmission line might be 500,000 volts and can handle more than 2000 amps. The strings of insulators are more than 10' long and the conductors are as thick as a baseball bat.
A powerful electrical testing lab might be able to produce 20,000 amps at 38,000 volts for fractions of a second.
20 kA x 38 kV = 760 MW
Note: The concept of "power factor" is considered to be beyond the scope of this question.
2007-06-27 05:05:20 · answer #1 · answered by Thomas C 6 · 3⤊ 0⤋
When thinking of this question you must consider the power. The relation between current, voltage and power in the simplest form can be shwon as following:
Apparent Power S (VA) = I(A) x V(V) or V(V)=S(VA)/I(A)
For a fixed power, if you increase voltage then current will decreae and vise versa. If you want to increase both current and voltage then you must increase the power.
2007-06-27 19:48:16 · answer #2 · answered by ASA 1 · 0⤊ 0⤋
For both current and voltage to be high, the resistance of the circuit must be extremely low. Low resistance material is expensive.
2007-06-27 04:17:05 · answer #3 · answered by lunatic 7 · 2⤊ 0⤋
A high current creates heat! Lots of heat!
2007-06-27 04:15:20 · answer #4 · answered by russfussuk 3 · 0⤊ 0⤋
If current is on the x axis then resistance is the slope; if voltage is on the x axis the slope is 1/v V = IR y= mx + b
2016-05-17 11:25:44 · answer #5 · answered by ? 3 · 0⤊ 0⤋
You would need a high power since power (VA) equals volts times amps.
2007-06-27 05:08:35 · answer #6 · answered by Poor one 6 · 0⤊ 0⤋
because most components cant take it that high
2007-06-27 04:20:28 · answer #7 · answered by thenovel_writer 2 · 1⤊ 0⤋
way too much power going on...
2007-06-27 04:17:09 · answer #8 · answered by Anonymous · 0⤊ 0⤋