Area of a four-walled hall is 660 sq m,length is twice the breadth and height 11m.Find the area of the ceiling

Question

The area of the four walls of a hall is 660 sq m, the length is twice the breadth and the height is 11 m.Find the area of the ceiling?
Options: (1) 200 sq m, (2) 300 sq m, (3) 400 sq m, (4) 500 sq m

Answer 1

W1 = 11 x
W2 = 22 x

Working EQUATION - 2(11 X) + 2(22 X) = 660
X = 10

area of ceiling = x (2x) = 200 sq.m.

Answer 2

A = 2(L + W)H = 660
(2W + W)11 = 330
3W = 30
W = 10
L = 20
Ceiling area = 200 m^2

Answer 3

200

Answer 4

quite, that's top cases width. of course, you ought to deduct for doors and abode windows. fairly than attempt to divide the room into little sections around the doors and abode windows, look on the wall as one vast rectangle devoid of the doors and abode windows, multiply that, then diploma the abode windows and door, multiply them,upload up those sums and deduct that comprehensive from the rectangle you first measured. in view that ceiling heights with the aid of the abode are often the comparable, you ought to use that dimension as a default, then you easily in user-friendly terms would desire to diploma horizontally. An occasion; a nicely-known 30" door would diploma, which incorporate 2 one million/2" casings, 35" x eighty 3" = 2905 sq. inches. There are one hundred forty four sq. inches in a sq. foot. So, to detect the sq. ft, divide one hundred forty four into 2905. answer is 20.17 sq. ft. or, 20 sq. ft.