power consumption of a super efficient freezer at 120V and 3A over a 24 hour period?

Question

power consumption of a super efficient freezer at 120V and 3A over a 24 hour period?

Answer 1

You are assuming the freezer runs continuously for 24 hours, which it doesn't.
I have a very old (25 yrs) huge chest freezer in my garage, definitely not built to today's efficiency standards, and in the Summer it costs me about $10 per month to operate it.
At $0.085/KWH, that's an average of 118 KWH/30 = 3.93 KWH/day.
In the winter, in the unheated garage, it is probably less than 1/2 of that.

Answer 2

If it uses 120 volts and three amps it has a power consumption of 120x3 = 360 watts. If it runs for 24 hours at that rate it would consume 8.64 kilowatt hours. Most regular-efficiency ones run about half the time so there goes about 4 kWh. If it was super efficient and everyone kept from opening the doors it might run only a quarter of the day so there is 2 kWh. At about 12 cents per kWh super efficiency would save you about 25 cents a day. Don't count on recouping the extra cost of a premium one with those savings. A typical refrigerator lasts for about 15 years so at $90 savings per year you would be luck to get back about $1300 over the lifetime compared to a standard one. That is a long wait for payback.

Answer 3

The correct term would be *energy* consumption. Power is the rate at which the energy is delivered and that is a constant 120 * 3 = 360 Watts = 360 Joules / second

24 hours * 60 minutes/hour * 60 seconds/minute = 86,400 seconds

The total energy consumed, then, is:

360 Joules / second * 86,400 seconds = 31.1 MegaJoules

It sounds like a lot, but 1 Joule isn't all that much energy. You can turn a swizel stick in an iced drink 20 times and barely generate 5 to 10 Joules.

kiloWattt-hours is another *energy* unit, like MegaJoules. The guys above put the energy consumption in terms of kWhr (which is also correct).

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Answer 4

Hold on a second guys .... Is it running constantly? .... not likely! If it's super-efficient, then it would probably be well insulated and well ventilated -- perhaps with a secondary coil to draw the heat away from the box.

If you know the cycling rate of the compressor, then multiply the above kWh by that rate.

Answer 5

120V x 3A = 360W x 1kW/1000W x 24 hrs = 8.64 kWh

Answer 6

I drink about three 32oz bottles a day.