one of the roots of xsq+x-3=0 is:?

Answer 1

to solve this problem you would use the quadratic formula

and putting in the values of A, B, & C

a = 1
b = 1
c = -3

and you get the roots

-1+(square root of 13) / 2

and

-1-(square root of 13) / 2

i didn't work it out to the decimal but a calculator can do that for you

Answer 2

x^2+x-3=0
one of its roots is?

Answer 3

u too lazy , that is only equation of the second degree ,
delta =13>0 so it sure has 2 roots

shound continue slove it on your self , good luck.

Answer 4

x^2+x-3 =0

discriminant 1-(-3)*4 = 13

roots x1= (-1+13^0.5)/2=1.30
x2= (-1-13^0.5)/2=-2.30