can someone give me a step-by-step soln to this qns pls?
btw the ans is: [(tan x) / 2] + c
2007-06-21 22:19:40 · 3 answers · asked by me 1 in Science & Mathematics ➔ Mathematics
Since cos 2x = 2 cos^2 x -1
So :
∫ 1/ (1 + cos 2x) dx = ∫ 1/ (2 cos^2 x ) dx
= ∫ 1/2 sec^2 x dx
= 1/2 tan x + c
2007-06-21 22:27:03 · answer #1 · answered by a_ebnlhaitham 6 · 1⤊ 0⤋
Integral 1/(1 + cos 2x ) dx
= Integral 1 / 2cos^2 ( x ) dx
= Integral ( 1/2 ) sec^2 ( x ) dx
= ( 1/2) tan ( x ) + c
= ( tan x ) / 2 + c
You are free to download study notes from my free educational website www.schoolnotes4u.com
2007-06-21 22:39:08 · answer #2 · answered by Madhukar 7 · 0⤊ 0⤋
cos 2x = 2 cos^2 x -1
∫ 1/ (1 + cos 2x) dx
= ∫ 1/ (1 + 2 cos^2 x - 1 ) dx
= ∫ 1/ (2 cos^2 x ) dx
= ∫ 1/2 sec^2 x dx
= 1/2(tan x) + c
2007-06-21 22:49:41 · answer #3 · answered by Tubby 5 · 0⤊ 0⤋
=integral of[(1/2cos^2 x)] dx=integral of1/2sec^2 x dx
=tan x /2. +c answer
2007-06-22 00:27:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
How are you going to learn and apply the skills you learn if you want someone else to do your homework for you? You are only cheating yourself!
2007-06-21 23:37:12 · answer #5 · answered by Anonymous · 0⤊ 0⤋
the ans [(tan x) / 2] + c is right!
2007-06-21 22:42:20 · answer #6 · answered by rui_min 1 · 0⤊ 0⤋