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one petal of r=cos 5 theta

2007-06-21 20:21:16 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

One petal extends from -pi/10 to +pi/10, so we integrate the expression from
theta = -pi/10
to
theta = pi/10.

integral(cos(5*theta),theta,-pi/10,pi/10)
= 1/5 * sin(5*theta), evaluated from -pi/10 to pi/10
= (1/5) - (-1/5)
= 1/5 + 1/5
= 2/5

The area of the petal is 2/5.

2007-06-21 20:32:51 · answer #1 · answered by lithiumdeuteride 7 · 0 0

it is part of application of integral calculus..its difficult here to show the calculations...

however i suggest you to view this site...
http://www.ltcconline.net/greenl/courses/107/premid2/polarea.htm

i hope this thing can help...

2007-06-22 03:36:17 · answer #2 · answered by Roger M 2 · 0 0

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