how do i factor out 4x^2-100
2007-06-21 18:45:31 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Difference of two squares.
(2x-10)(2x+10)
2(x-5)*2(x+5)
4(x-5)(x+5)
2007-06-21 18:48:08 · answer #1 · answered by jsoos 3 · 0⤊ 0⤋
4x^2 - 100
= 4(x^2 - 25)
= 4(x+5)(x-5)
2007-06-22 01:53:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4x^2-100
=4(x^2 - 25)
=4(x^2 - 5^2)
=4(x + 5)(x - 5)#
2007-06-22 01:54:33 · answer #3 · answered by jackleynpoll 3 · 0⤊ 0⤋
it's diffrence of perfect squares
a^2 - b^2 = (a - b) (a + b)
4x^2 - 100
= 2^2 x^2 - 10^2
= (2x)^2 - 10^2
= (2x - 10) (2x + 10)
2007-06-22 01:48:26 · answer #4 · answered by 7 · 0⤊ 0⤋
divide out four. 4(x^2-25). then factor the squares. 4(x+5)(x-5)
2007-06-22 01:50:06 · answer #5 · answered by Justin Z 2 · 0⤊ 0⤋
= 4.(x² - 25)
= 4.(x - 5).(x + 5)
2007-06-22 02:15:46 · answer #6 · answered by Como 7 · 0⤊ 0⤋