x-int=0, y-int=0 so the start at (0,0). slope of three so up three over one. (0,0), (3,1), (6,2) and so forth. also go the down three left one below (0,0)
2007-06-21 18:48:41
·
answer #1
·
answered by Justin Z 2
·
0⤊
0⤋
The graph of y=3x is a straight line with a gradient of 3 and a y-intercept of 0.
2007-06-21 18:56:04
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
Points on graph are (0,0) , (4,12) , (6,18)
Graph may now be drawn.
Will be a straight line of gradient (slope) 3 that passes thro` the origin.
2007-06-21 19:17:53
·
answer #3
·
answered by Como 7
·
0⤊
0⤋