2007-06-21 17:01:37 · 4 answers · asked by aoc10010001100 2 in Science & Mathematics ➔ Mathematics
Do your own homework please. You'll learn more that way!
2007-06-21 17:04:07 · answer #1 · answered by ((♫♥♪♫♥♪♫ Shivers ♫♥♪♫♥♪)) 5 · 0⤊ 2⤋
u can first multiply
(9-y)y^(1/2) = [9y^(1/2)]-y^(3/2)
so u can solve this easy
integrate[9y^(1/2)]-y^(3/2)dy=
integrate[9y^(1/2)]dy - integrate[y^(3/2)]=
9 integ.(y^1/2)dy - integrate[y^(3/2)]dy=
9[2/3y^(3/2)] - (2/5)y^(5/2)=
(18/3) y^(3/2) - (2/5)y^(5/2)=
6y^(3/2) - (2/5)y^(5/2)
2007-06-22 00:12:02 · answer #2 · answered by cecy e 2 · 0⤊ 1⤋
cecy e has it *almost* right...never forget your constants when you are integrating!!!
so, using cecy e's method, the end result is 6y^(3/2) - (2/5)y^(5/2) + 9a + b where a,b are constants...
you can also factor more thoroughly to get: (2/5)(y^(3/2))(15-y) + 9a + b
good luck!! :)
2007-06-22 00:42:44 · answer #3 · answered by CM 2 · 0⤊ 1⤋
expand, then integrate:
[9y^(1/2) - y^(3/2)]dy
2007-06-22 00:12:35 · answer #4 · answered by Helmut 7 · 0⤊ 2⤋