2007-06-21 16:58:07 · 9 answers · asked by matcav2002 1 in Science & Mathematics ➔ Mathematics
5x^2 + 17x + 14
5x^2 +10x+7x+14
5x(x+2) +7(x+2)
(x+2)(5x+7)
2007-06-21 17:00:27 · answer #1 · answered by sweet n simple 5 · 0⤊ 2⤋
(5x + 7).(x + 2)
Check
5x.(x + 2) + 7.(x + 2)
5x² + 10x + 7x + 14
5x² + 17x + 14 (as required)
2007-06-21 19:49:46 · answer #2 · answered by Como 7 · 0⤊ 1⤋
Factors of 5 can only be 5 and 1.
Factors of 14 can only be 1 and 14, or 2 and 7.
So just trying all these, the answer is
(5x+7)(x+2)
.
2007-06-21 17:01:45 · answer #3 · answered by tsr21 6 · 0⤊ 3⤋
5x^2+17x+14
=5x^2+10x+7x+14
=5x(x+2)+7(x+2)
=(x+2)(5x+7)
2007-06-21 20:27:54 · answer #4 · answered by shiva 3 · 0⤊ 1⤋
5x^2+17x+14
=5x^2+10x+7x+14
=5x(x+2)+7(x+2)
=(5x+7)(x+2)
2007-06-21 17:03:42 · answer #5 · answered by alpha 7 · 1⤊ 1⤋
(5x+7)(x+2)
2007-06-21 19:52:50 · answer #6 · answered by Irwan 2 · 1⤊ 1⤋
(5x+7)(x+2)
2007-06-21 17:00:18 · answer #7 · answered by -entropy! 3 · 0⤊ 1⤋
5x^2 + 17x + 14=0
5x+7)(x+2)=0
(5x+7)(x+2)=0
--------------------
(5x+2)
x+2=0
..-2 -2
---------
x= -2
(5x+7)(x+2)=0
-------------------
(x+2)
5x+7=0
....-7 -7
-----------
5x=-7
-----------
5
x= -7
x= -2
x= -7
2007-06-21 21:01:29 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(5x+7)(x+2)
2007-06-21 17:02:26 · answer #9 · answered by cecy e 2 · 0⤊ 2⤋