algebra 2 help?

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At time t = 0 hours, there are 500 bacteria in a favorable growth medium. 5 hours later, there are 2000 bacteria. Assuming exponential growth, what is the growth constant "k" for the bacteria?

A 0.155
B 2.543
C 0.135
D 0.277
E 1.467
F 1.866

2007-06-21 16:48:17 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

E ......idk im only in 6th gr.

2007-06-21 16:52:16 · answer #1 · answered by ●※Sёιεηα＿↑ 2 · 0⤊ 1⤋

A = (Ao) e^(kt)
500 = Ao (when t = 0)
2000 = 500.e^(5k)
4 = e^(5k)
ln 4 = 5k.ln e
ln 4 = 5k
k = ln 4 / 5
k = 0.277
OPTION D

2007-06-24 13:53:59 · answer #2 · answered by Como 7 · 0⤊ 0⤋