I'm not quite sure how to do this problem.
x^-6y^-2/z^-5
What do you do after you reach
1/x^6*1/y^2*z^5
2007-06-21 15:58:23 · 5 answers · asked by MRBrocks 1 in Science & Mathematics ➔ Mathematics
You could go one further and write
z^5 / (x^6 y^2)
2007-06-21 16:03:53 · answer #1 · answered by Dr D 7 · 1⤊ 0⤋
No. Assuming I can figure out what you were TRYING (but failing) to write
(x^(-6)) * (y^(-2)) / (z^(-5)) is
1 / ( x^6 * y²) * z^5 or { (z^5) / [ (x^6)*(y²) ] }
because
1 / (z^-5) is 1 / ( 1 / (z^5)) = z^5 like 1 / (1/2) is 2, see?
2007-06-21 23:09:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
When you multiply fractions, multiply all the numerators and all the denominators so you get
[z^5] / [x^6 * y^2]
2007-06-21 23:03:31 · answer #3 · answered by piggy30 3 · 0⤊ 0⤋
Assume question reads:-
x^(- 6).y^(- 2) / z^(- 5)
= z^(5) / [ x^(6).y^(2) ]
2007-06-22 03:03:38 · answer #4 · answered by Como 7 · 0⤊ 0⤋
No wonder you can't figure it out....obviously failed in spelling...it's spelled...dividing.
2007-06-21 23:07:59 · answer #5 · answered by wild_cherry63 1 · 0⤊ 0⤋