Given the parobola y=(x+4)^2 - 2. Find the vertex and axis.
2007-06-21 15:37:33 · 5 answers · asked by stlcurtain_1 1 in Science & Mathematics ➔ Mathematics
y = (x + 4)^2 - 2
the equation is in the vertex form y = a(x - h)^2 + k with the vertex of (h,k)
the vertex of the equation above is (-4,-2)
2007-06-21 15:47:09 · answer #1 · answered by 7 · 0⤊ 0⤋
y = [ (x - (- 4) ] ² - 2
Vertex (- 4 , - 2)
Axis of symmetry is x = - 4
2007-06-24 13:42:51 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Vertex( -4, -2)
AOS: x=-4
2007-06-21 22:45:50 · answer #3 · answered by ania 2 · 0⤊ 0⤋
vertex = (-4,-2)
x interpects = -5.41 and -2.58
2007-06-21 22:49:55 · answer #4 · answered by Wheels 3 · 0⤊ 0⤋
ummm your still in school? I just took algebra and i forget that already. sorry.
2007-06-21 22:44:55 · answer #5 · answered by lchick93 2 · 0⤊ 1⤋