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can anyone help me with just two problems? here theyare:

4x2 - 8x + 16 = 0
1

2

4


x2 - 6x + 5 = 0
9

7

6


thanks so much for all of your answers!!

2007-06-21 14:45:01 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

4x² - 8x + 16 = 0
x² - 2x + 4 = 0

[ (-2)/2 ]² = 1

x² - 6x + 5 = 0

[ (-6)/2 ]² = 9

1 and 9

2007-06-21 14:49:08 · answer #1 · answered by MathGuy 6 · 0 0

1 and 9

2007-06-21 14:48:27 · answer #2 · answered by Anonymous · 0 0

Question 1
x² - 2x = - 4
(x² - 2x + 1) = - 4 + 1
(x - 1)² = - 3
(x - 1) = ± √(3i²)
(x - 1) = ± i √3
1 has been added to both sides.

Question 2
x² - 6x = - 5
x² - 6x + 9 = - 5 + 9
(x - 3)² = 4
(x - 3) = ± 2
x = 3 ± 2
x = 1 , x = 5
9 has been added to both sides.

2007-06-23 23:36:03 · answer #3 · answered by Como 7 · 0 0

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